Tính tổng S=2+7+12+....197+202
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\(9^{12}.19-3^{24}.19\\ =\left(3^2\right)^{12}.19-3^{24}.19\\ =3^{24}.19-3^{24}.19=0\)

2x+1 -2x-1 = 52 - 50
2x+1 - 2x-1 = 24
2x-1.(22-1) = 24
2x-1.3 = 24
2x-1 = 24 : 3
2x-1 = 8
2x-1 = 23
x - 1 = 3
x = 4
2x = 52
2x+1 -2x-1 = 52 - 50
2x+1 - 2x-1 = 24
2x-1.(22-1) = 24
2x-1.3 = 24
2x-1 = 24 : 3
2x-1 = 8
2x-1 = 23
x - 1 = 3
x = 4
2x = 52

Ta có:
\(A=2020^{2023}-2020^{2022}=2020^{2022}\left(2020-1\right)=2019.2020^{2022}\\ B=2020^{2022}-2020^{2021}=2020^{2021}\left(2020-1\right)=2019.2020^{2021}\)
\(A-B=2019.2020^{2022}-2019.2020^{2021}=2019.2020^{2021}\left(2020-1\right)>0\\ \Rightarrow A>B\)
A=20202023−20202022=20202022(2020−1)=2019.20202022B=20202022−20202021=20202021(2020−1)=2019.20202021
A-B=2019.2020^{2022}-2019.2020^{2021}=2019.2020^{2021}\left(2020-1\right)>0\\ \Rightarrow A>BA−B=2019.20202022−2019.20202021=2019.20202021(2020−1)>0⇒A>B

\(\left\{132-\left[116-\left(16-8\right)\right]:2\right\}.5\)
\(=\left\{132-\left[116-8\right]:2\right\}.5\)
\(=\left\{132-108:2\right\}.5\)
\(=390\)


\(3.5^x-8=367\)
\(\Leftrightarrow3.5^x=375\)
\(\Leftrightarrow5^x=125\)
\(\Leftrightarrow x=3\)

Có tất cả các số trên dãy là: (202-2):4+1=51(số)
Tổng dãy số trên là: (202+2)x51:2=5202