2xy+z+2x+yz

= 2x(y+1)+z(y+1)

= (y+1)(2x+z)

x^3+x^2y-3x^2+xy+y^2-4y-x+3
=(x^3+x^2y-3x^2)+(xy+y^2-3y)-(x+y-3)
=x^2(x+y-3)+y(x+y-3)-(x+y-3)
=(x+y-3)(x^2+y-1)
=0(x^2+y-1) ( vì x+y=3)
chúc bạn học tốt

??? mink đ4nq h0i T04n m4k?

dễ vãi lol ra bn ngu vãi đái

a, \(\left(x-y+4\right)^2-\left(2x+3y-1\right)^2=\left(x-y+4+2x+3y-1\right)\left(x-y+4-2x-3y+1\right)\)

\(=\left(3x+2y+3\right)\left(-x-4y+5\right)\)

b, \(x^6+y^6=\left(x^2\right)^3+\left(y^2\right)^3=\left(x^2+y^2\right)\left(x^4-x^2y^2+y^4\right)\)

c, \(x^{16}-1=\left(x^2\right)^8-1=\left[\left(x^2\right)^4\right]^2-1=\left(x^8-1\right)\left(x^8+1\right)\)

\(x\cdot x\cdot x+2y\left(x+1\right)+1\)

\(x^3+2xy+y+1\)

\(x\left(x^2+2y+y\right)+1\)

chỉ bt chừng đó thôi

a - b = 6

=> ( a - b )² = 36

=> a² - 2ab + b² = 36

<=> a² + 2ab + b² - 4ab = 36

<=> ( a + b )² - 4.16 = 36

<=> ( a + b )² = 100

<=> a + b = ±10

A = x² - 3x + 5 ( x² chứ nhể )

= ( x² - 3x + 9/4 ) + 11/4

= ( x - 3/2 )² + 11/4 ≥ 11/4 ∀ x

Dấu "=" xảy ra <=> x = 3/2

=> MinA = 11/4 <=> x = 3/2

B = ( 2x - 1 )² + ( x + 2 )²

= 4x² - 4x + 1 + x² + 4x + 4

= 5x² + 5 ≥ 5 ∀ x

Dấu "=" xảy ra khi x = 0

=> MinB = 5 <=> x = 0 

A = x⁶ - 2x⁴ + x³ + x² - x

= x⁶ - x⁴ - x⁴ + x³ + x² - x

= ( x⁶ - x⁴ ) - ( x⁴ - x² ) + ( x³ - x )

= x³( x³ - x ) - x( x³ - x ) + ( x³ - x )

= ( x³ - x )( x³ - x + 1 )

= 6( 6 + 1 )

= 6.7 = 42