\(3:\left|x-1\right|=27:\left|1-x\right|\left(ĐK:x\ne1\right)\)

\(\Rightarrow3:\left|x-1\right|-27\left|x-1\right|=0\)

\(\Rightarrow\left(3-27\right):\left|x-1\right|=0\)

\(\Rightarrow-24:\left|x-1\right|=0\)

\(\Rightarrow\left|x-1\right|=0\)

\(\Rightarrow x=1\) (Loại)

(x-2/3)^2=2^2

(x-2/3)=2

x=2+2/3 =8/3

\(\left(x-\frac{2}{3}\right)^2=\left(-4\right)\)

\(\Rightarrow\text{Không tìm đc x}\)

Ta có :

\(\left(x-\frac{2}{3}\right)^2\ge0\forall x\in Z\)

Mà \(\left(x-\frac{2}{3}\right)^2=-4\)

=> x ∈ Ø

Vậy x ∈ Ø

~~Học tốt~~

'-' cái gì dạ '-'

what-_-, chuyện j đang xảy ra?

Ta có : | 3x - 5 | = -2x + 6

\(\Rightarrow\begin{cases}3x-5=-2x+6\\3x-5=2x-6\end{cases}\)

\(\Rightarrow\orbr{\begin{cases}3x-\left(-2x\right)=6+5=11\\2x-3x=6-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}5x=11\\-x=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{11}{5}\\x=-1\end{cases}}\)

c) \(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)

\(=\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{3}+\frac{1}{6}\right)+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)

\(=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\) (1)

\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\) (2)

Ta có: (2) - (1) được: \(A=1-\frac{1}{128}\Rightarrow A=\frac{127}{128}\)

d) \(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)

\(=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)

\(=\left(3-5-6\right)+\left(\frac{7}{4}-\frac{1}{4}-\frac{3}{2}\right)+\left(\frac{2}{3}-\frac{1}{3}\right)+\frac{6}{5}\)

\(=-8+\frac{7-1-6}{4}+\frac{1}{3}+\frac{6}{5}\)

\(=\frac{1}{3}+\frac{6}{5}-8=\frac{5+18-120}{15}=\frac{-97}{15}\)

\(\frac{6^3+3.6^2+3^3}{-13}\)

\(=\frac{2^3.3^3+3.3^2.2^2+3^3}{-13}\)\(=\frac{2^3.3^3+3^3.2^2+3^3}{-13}\)\(=\frac{3^3\left(2^3+2^2+1\right)}{-13}\)\(=\frac{3^3.13}{-13}=-27\)

ok thank 

HT

okk bạn

Theo đề bài ra, ta có:

\(3a=8b\Rightarrow\frac{a}{8}=\frac{b}{3}\)

Áp dụng tính chất của dãy tỷ số bằng nhau

\(\frac{a}{8}=\frac{b}{3}=\frac{a+b}{8+3}=\frac{33}{11}=3\)

\(\Rightarrow\frac{a}{8}=3\Rightarrow a=8.3=24\)

\(\Rightarrow\frac{b}{3}=3\Rightarrow b=3.3=9\)