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a) \(\left(-\frac{2}{3}\right)^2:\frac{1}{3}-\left|-1\frac{1}{2}\right|=\frac{4}{9}:\frac{1}{3}-\frac{3}{2}=\frac{4}{3}-\frac{3}{2}=-\frac{1}{6}\)
b) \(\left(\frac{1}{2}-\frac{3}{5}\right)^2+\frac{2}{3}\left|\frac{3}{4}-\frac{1}{2}\right|+2012^0=\left(-\frac{1}{10}\right)^2+\frac{2}{3},\frac{1}{4}+2012^0\)
\(=\frac{1}{100}+\frac{1}{6}+1=\frac{353}{300}\)
c) \(\left(3^2:\frac{1}{3}\right)+2^3+\frac{1}{2}+\frac{1}{4}-6=3^3+2^3+\frac{3}{4}-6=29\frac{3}{4}\)
\(3\left(2x+1\right)^2-5=22\)
\(\Rightarrow3\left(2x+1\right)^2=27\)
\(\Rightarrow\left(2x+1\right)^2=9\)
\(\Rightarrow\left(2x+1\right)^2-3^2=0\)
\(\Rightarrow\left(2x+1-3\right)\left(2x+1+3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-2=0\\2x+4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-2\end{cases}}\)
\(a,\left(\frac{1}{5}\right)^5.5^5\)\(=0\)
\(b,\left(0,125\right)^3.512\)\(=1\)
\(c,\left(0,25\right)^4.1024\)\(=4\)
~ Hok tốt nhé ~ ^^^
TL
Tính :
a) ( 1/5 )5.55=0
b) ( 0,125 )3.512=1
c) ( 0,25 )4.1024=4
HT
Ta có :
850 = ( 23 )50 = 2150 > 2136 = ( 22 )68 = 468
=> 850 > 468
Vậy 850 > 468
\(\frac{2^{15}.9^4}{6^6.8^3}\)
\(=\)\(\frac{2^{15}.\left(3^2\right)^4}{\left(3.2\right)^6.\left(2^3\right)^3}\)
\(=\)\(\frac{2^{15}.3^8}{3^6.2^6.2^9}\)
\(=\)\(\frac{2^{15}.3^6.3^2}{3^6.2^{15}}\)
\(=\)\(3^2=9\)
N P x M Q 40 o 1 2 1
Ta có : \(\widehat{M_1}=\widehat{M_2}\)( do là 2 góc đối đỉnh )
Mà \(\widehat{M_1}=40^o\)\(\Rightarrow\widehat{M_3}=40^o\)
Lại có : \(\widehat{M_3}=\widehat{P_1}\)( do là 2 góc đồng vị )
\(\Rightarrow\widehat{P_1}=40^o\)mà \(\widehat{P_1}+x=180^o\)
\(\Rightarrow40^o+x=180^o\)
\(\Rightarrow x=180^o-40^o=140^o\)