giúp mình đi 

nhanh nhé

2^15*9^4/6^6*8^3

= 2359296

HT

​\(\frac{2^{15}.9^4}{6^6.8^3}\)=\(\frac{2^{15}.3^8}{2^6.3^6.2^9}\)=3²=9

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ann phải viết rõ chứ em ko giải được em lớp 4 nhưng mà em biết giải em học rồi

Ta có : \(\hept{\begin{cases}AB⊥BC\\CD⊥BC\end{cases}}\)=> AB // DC

=> \(\widehat{IAB}=\widehat{FIC}\Rightarrow\widehat{FIC}=45^o\)

Ta có : \(\widehat{FIC}+\widehat{AIC}=180^o\)

\(\Rightarrow\widehat{AIC}=180^o-45^o=135^o\)

b) Vì \(\hept{\begin{cases}DC⊥DE\\EF⊥DE\end{cases}}\)=> DC // EF mà DC // AB ( phần a )

=> AB // EF

c) Vì \(\widehat{FIC}=\widehat{IFE}\)( do là 2 góc so le trong )

=> \(\widehat{IFE}=45^o\)

a) \(\left|x+\frac{1}{3}\right|=0\)

\(\Rightarrow x+\frac{1}{3}=0\)

\(\Rightarrow x=\frac{-1}{3}\)

b) \(\left|x\right|-\frac{3}{5}=\frac{5}{9}\)

\(\Rightarrow\left|x\right|=\frac{52}{45}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{52}{45}\\x=\frac{-52}{45}\end{cases}}\)

c) \(\left|x+\frac{3}{4}\right|=\frac{1}{2}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=\frac{-1}{2}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{4}\\x=\frac{-5}{4}\end{cases}}\)

d) \(\left(\frac{-5}{9}\right)^{10}:x=\left(\frac{-5}{9}\right)^8\)

\(\Rightarrow\left(\frac{-5}{9}\right)^{10}:\left(\frac{-5}{9}\right)^8=x\)

\(\Rightarrow x=\left(\frac{-5}{9}\right)^2=\frac{25}{81}\)

e) \(x:\left(-\frac{5}{9}\right)^8=\left(-\frac{5}{9}\right)^8\)

\(\Rightarrow x=\left(-\frac{5}{9}\right)^8.\left(-\frac{5}{9}\right)^8\)

\(\Rightarrow x=\left(-\frac{5}{9}\right)^{16}=\left(\frac{5}{9}\right)^{16}\)

f) x³ = -8

=> x³ = ( -2 )³

=> x = -2

g) ( x + 5 )³ = -27

=> ( x + 5 )³ = ( -3 )³

=> x + 5 = -3

=> x = -8

h) ( 2x - 3 )³ = -64

=> ( 2x - 3 )³ = ( -4 )³

=> 2x - 3 = -4

=> 2x = -1

=> x = -0,5

i) ( 2x - 3 )² = 25

=> ( 2x - 3 )² = 5² = ( -5 )²

\(\Rightarrow\orbr{\begin{cases}2x-3=5\\2x-3=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x=8\\2x=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-1\end{cases}}\)

hieu gi chet lien

la du ta seo vua dung lai thanh sai.cha nhe mat mo ta