\(\left|3x-5\right|+\left(2y+5\right)^{208}+\left(4z-3\right)^{20}\le0\)

\(\Leftrightarrow\hept{\begin{cases}3x-5=0\\2y+5=0\\4z-3=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=\frac{5}{3}\\y=-\frac{5}{2}\\z=\frac{3}{4}\end{cases}}\)

TL:
 

1 + 1 = 3

1 + 1 = 11

Cái dạng này thì có nhiều câu trả lời mà

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_____________( ' _ ' ) ______________

 Đúng ko???

1+1=11 à bn

 Xin chào 

báo cáo giang nha

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\left(\frac{2}{3}\right)^2+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}+\frac{4}{9}.\left(-\frac{1}{8}\right)\).

\(=\frac{4}{9}.1+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}.\left(-\frac{1}{8}+1\right)\)

\(=\frac{4}{9}.\frac{7}{8}\)

\(=\frac{7}{18}\)

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{2^2}{9}.\frac{-1}{2^3}\)

\(=\left(\frac{2}{3}\right)^2+\frac{-1}{18}\)\(=\frac{4}{9}-\frac{1}{18}=\frac{7}{18}\)

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{2^2}{9}.\frac{-1}{2^3}\)

\(=\left(\frac{2}{3}\right)^2+\frac{-1}{18}\)

\(=\frac{4}{9}-\frac{1}{18}=\frac{7}{18}\)

Đặt \(\frac{a}{b}=\frac{c}{d}=t\Rightarrow\hept{\begin{cases}a=bt\\c=dt\end{cases}}\)

\(\frac{a^2-c^2}{b^2-d^2}=\frac{\left(bt\right)^2-\left(dt\right)^2}{b^2-d^2}=t^2\)

\(\frac{ac}{bd}=\frac{bt.dt}{bd}=t^2\)

Suy ra đpcm. 

TL

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Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!