1000 số 1 =))

999999999999999999999999999999999999×9×99×999×9999×99999×999999×9999999×99999999×999999999×9999999999×99999999999×999999999999×9999999999999×99999999999999×999999999999999×9999999999999999×99999999999999999×999999999999999999×9999999999999999999×99999999999999999999=?

Vì \(\left|x+2\right|\ge0;\left|x+4\right|\ge0;\left|x+8\right|\ge0\Leftrightarrow2021x\ge0\Leftrightarrow x\ge0\)

\(\Rightarrow\left|x+2\right|=x+2;\left|x+4\right|=x+4;\left|x+8\right|=x+8\)

\(\Rightarrow x+2+x+4+x+8=2021x\)

\(\Leftrightarrow3x+14=2021x\)

\(\Leftrightarrow2021x-3x=14\)

\(\Leftrightarrow2018x=14\)

Từ đó tìm được x nha

khos thees

blqjhjghj

\(\left|\frac{x+2}{5}\right|=\left|\frac{2x-1}{3}\right|\)

<=> \(\orbr{\begin{cases}\frac{x+2}{5}=\frac{2x-1}{3}\\\frac{x+2}{5}=\frac{1-2x}{3}\end{cases}}\Leftrightarrow\orbr{\begin{cases}3\left(x+2\right)=5\left(2x-1\right)\\3\left(x+2\right)=5\left(1-2x\right)\end{cases}}\Leftrightarrow\orbr{\begin{cases}7x=11\\13x=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{7}\\x=-\frac{1}{13}\end{cases}}\)

Vậy \(x\in\left\{\frac{11}{7};-\frac{1}{13}\right\}\)

 ảnh chụp

Ta có ax + by = c ; by + cz = a

<=> cz - ax = a - c (1)

mà cz + ax = b (2) 

Từ (1) và (2) => \(cz=\frac{a-c+b}{2}\Rightarrow z=\frac{a-c+b}{2c}\Rightarrow z+1=\frac{a+b+c}{2c}\)

=> \(\frac{1}{z+1}=\frac{2c}{a+b+c}\)

Tương tự ta có \(\frac{1}{x+1}=\frac{2a}{a+b+c}\); \(\frac{1}{y+1}=\frac{2b}{a+b+c}\)

=> P = \(\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1}=\frac{2a}{a+b+c}+\frac{2b}{a+b+c}+\frac{2c}{a+b+c}=2\)

nguồn:https://olm.vn/hoi-dap/detail/327640299239.html

3 m nha

mik bt làm nhưng đang bận và lười