1. Tính hợp lí

a) \(0,7+\dfrac{-7}{19}-\left(-0,3\right)\)

\(=\dfrac{7}{10}+\dfrac{-7}{19}+\dfrac{3}{10}\)

\(=\left(\dfrac{7}{10}+\dfrac{3}{10}\right)+\dfrac{-7}{19}\)

\(=1+\dfrac{-7}{19}\)

\(=\dfrac{12}{19}\)

b) \(\dfrac{5}{3}.\left(-2,5\right):\dfrac{5}{6}\)

\(=\dfrac{5}{3}.\dfrac{-5}{2}.\dfrac{6}{5}\)

\(=\left(\dfrac{5}{3}.\dfrac{6}{5}\right).\dfrac{-5}{2}\)

\(=2.\dfrac{-5}{2}\)

\(=-5\)

c) \(0,6.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)

\(=\dfrac{3}{5}.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)

\(=\dfrac{3}{5}.\left(\dfrac{-5}{17}-\dfrac{12}{17}\right)\)

\(=\dfrac{3}{5}.-1\)

\(=\dfrac{-3}{5}\)

d) \(\dfrac{7}{4}.\dfrac{5}{2}-\dfrac{7}{4}.\dfrac{3}{2}\)

\(=\dfrac{7}{4}.\left(\dfrac{5}{2}-\dfrac{3}{2}\right)\)

\(=\dfrac{7}{4}.1\)

\(=\dfrac{7}{4}\)

Chúc bạn học tốt

a) 0,7+−719−(−0,3)0,7+19−7​−(−0,3)

=710+−719+310=107​+19−7​+103​

=(710+310)+−719=(107​+103​)+19−7​

=1+−719=1+19−7​

=1219=1912​

b) 53.(−2,5):5635​.(−2,5):65​

=53.−52.65=35​.2−5​.56​

=(53.65).−52=(35​.56​).2−5​

=2.−52=2.2−5​

$=-5$

c) 0,6.−517−35.12170,6.17−5​−53​.1712​

=35.−517−35.1217=53​.17−5​−53​.1712​

=35.(−517−1217)=53​.(17−5​−1712​)

=35.−1=53​.−1

=−35=5−3​

d) 74.52−74.3247​.25​−47​.23​

=74.(52−32)=47​.(25​−23​)

=74.1=47​.1

=74=47​

mình giúp rùi đó nhớ tick mình nha

\(2^x\cdot2=128\)

\(\Rightarrow2^x=128:2\)

\(\Rightarrow2^x=64\)

\(\Rightarrow2^x=2^6\)

\(\Rightarrow x=6\)

==============

\(4^x:4^3=16\)

\(\Rightarrow4^{x-3}=16\)

\(\Rightarrow4^{x-3}=4^2\)

\(\Rightarrow x-3=2\)

\(\Rightarrow x=3+2=5\)

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\(2^x:3=48\)

\(\Rightarrow2^x=48:3\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

==============

\(3^{x-5}=81\)

\(\Rightarrow3^{x-5}=3^4\)

\(\Rightarrow x-5=4\)

\(\Rightarrow x=4+5\)

\(\Rightarrow x=9\)

2ˣ⁻² = 128

2ˣ⁻² = 2⁷

x - 2 = 7

x = 7 + 2

x = 9

Các câu còn lại xem bài bạn Phong

\(71+65.4=\dfrac{\left(x+140\right)}{x}+260\) \(\left(x\ne0\right)\)

\(\Leftrightarrow71.x+65.4.x=x+140+260.x\)

\(\Leftrightarrow70x=140\Rightarrow x=140:70=2\)

\(71+65.4=\dfrac{\left(x+140\right)}{x}+260\left(x\ne0\right)\Leftrightarrow71+260=\dfrac{\left(x+140\right)}{x}+260\)

\(\Leftrightarrow71=\dfrac{\left(x+140\right)}{x}\)\(\Leftrightarrow71x=x+140\Leftrightarrow70x=140\)

\(\Leftrightarrow x=2\) (thoả mãn đk)

Vậy phương trình có nghiệm duy nhất là x=2

Chiều rộng của bể:

\(3\times\dfrac{3}{4}=2,25\left(m\right)\)

Thể tích của bể:

\(3\times2,25\times1,4=9,45\left(m^3\right)\)

Sau một tuần sử dụng thì thể tích nước còn lại trong bể:

\(9,45\times40\%=3,78\left(m^3\right)\)

Thể tích của bể không có nước là:

\(9,45-3,78=5,67\left(m^3\right)\)

Số tiền mà Nam sử dụng để mua nước trong 1 tuần:

\(5,67\times10000=56700\left(đ\right)\)

Đáp số: 56700 (đ)

BCNN(50;8;20)=200

B(200)={0;200;400;600;800;1000;....}

Số nguyên dương có 3 chữ số là {200;400;600;800}

\(\dfrac{14,75+B}{10,85-B}=0,6\)

\(\Rightarrow\dfrac{14,75+B}{10,85-B}=\dfrac{0,6.\left(10,85-B\right)}{10,85-B}\) \(\left(B\ne10,85\right)\)

\(\Rightarrow14,75+B=0,6.10,85-0,6B\)

\(\Rightarrow B+0,6B=6,51-14,75\)

\(\Rightarrow1,6B=-8,24\)

\(\Rightarrow B=-5,15\)

`@` `\text {Ans}`

`\downarorw`

`2^x \div 2 = 128?`

`=> 2^x = 128 * 2`

`=> 2^x = 256`

`=> 2^x = 2^8`

`=> x = 8`

Vậy, `x = 8`

______

`4^x \div 4^3 = 16`

`=> 4^x = 16 * 4^3`

`=> 4^x = 4^2 * 4^3`

`=> 4^x = 4^5`

`=> x = 5`

Vậy, ` x = 5`

________

`12^x \div 3 = 48 ?`

`=> 12^x = 48 * 3`

`=> 12^x = 144`

`=> 12^x = 12^2`

`=> x = 2`

Vậy, `x = 2`

________

`3^x - 5 = 81`

`3^x = 81 + 5`

`3^x = 86`

Bạn xem lại đề

`@` `\text {Kaizuu lv uuu}`

4 \(\times\) (\(x-1\))³ - 1 = 3

4 \(\times\) (\(x\) - 1)³ = 3 + 1

4 \(\times\) (\(x-1\))³ = 4

      (\(x-1\))³ = 4:4

      (\(x-1\))³ = 1

      \(x-1=1\)

     \(x\) = 1 + 1

     \(x\) = 2 

`@` `\text {Ans}`

`\downarrow`

`x^3 = 125`

`=> x^3 = 5^3`

`=> x = 5`

Vậy, `x = 5`

_____

`4^5 \div 4^3`

`=`\(4^{5-3}\)

`= 4^2`

______

\(8^{12}\cdot8^3\div8^{15}\)

`=`\(8^{12+3-15}\)

`=`\(8^0=1\)

______

\(7^{15}\div7^{13}\)

`=`\(7^{15-13}\)

`=`\(7^2\)

_______

\(17^{15}\cdot17^{10}\div17^{22}\)

`=`\(17^{15+10-22}\)

`= 17^3`

_______

\(5^{10}\cdot25\div5^{11}\)

`=`\(5^{10}\cdot5^2\div5^{11}\)

`=`\(5^{10+2-11}\)

`= 5`

_______

\(15^{10}\cdot225\div15^{11}\)

`=`\(15^{10}\cdot15^2\div15^{11}\)

`=`\(15^{12}\div15^{11}\)

`= 15`

`@` `\text {Kaizuu lv uuu}`

\(x^3=125\)

\(\Rightarrow x^3=5^3\)

\(\Rightarrow x=3\)

___________________

\(4^5:4^3\)

\(=4^{5-3}\)

\(=4^2=16\)

___________________

\(8^{12}.8^3:8^{15}\)

\(=8^{15}:8^{15}\)

\(=1\)

___________________

\(7^{15}:7^{13}\)

\(=7^{15-13}\)

\(=7^2=49\)

___________________

\(17^{15}.17^{10}:17^{22}\)

\(=17^{25}:17^{22}\)

\(=17^3=4913\)

___________________

\(5^{10}.25:5^{11}\)

\(=5^{10}.5^2:5^{11}\)

\(=5^{12}:5^{11}\)

\(=5^1=5\)

___________________

\(15^{10}.225:15^{11}\)

\(=15^{10}.15^2:15^{11}\)

\(=15^{12}:15^{11}\)

\(=15^1=15\)

__________________

* aⁿ . a^m = a^n+m

 aⁿ : a^m = a^n-m

Chúc bạn học tốt

7 chiếc là 350 000 dồng