cho góc xAy và điểm M thuộc miền trong của góc ấy .Xác định vị trí của đường thẳng d đi qua M cắt Ax, Ay lần lượt tại B, C sao cho M là trung điểm BC
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\(4x^2+4x=80\Leftrightarrow4x^2+4x-80=0\)
\(\Leftrightarrow4x^2+4x+1-81=0\Leftrightarrow\left(2x+1\right)^2-9^2=0\)
\(\Leftrightarrow\left(2x-8\right)\left(2x+10\right)=0\Leftrightarrow x=4;x=-5\)
Trả lời:
\(4x^2+4x=80\)
\(\Leftrightarrow4x^2+4x-80=0\)
\(\Leftrightarrow4x^2+4x+1-81=0\)
\(\Leftrightarrow\left(4x^2+4x+1\right)-81=0\)
\(\Leftrightarrow\left(2x+1\right)^2-81=0\)
\(\Leftrightarrow\left(2x+1-9\right)\left(2x+1+9\right)=0\)
\(\Leftrightarrow\left(2x-8\right)\left(2x+10\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-8=0\\2x+10=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-5\end{cases}}}\)
Vậy x = 4; x = - 5 là nghiệm của pt.
Không đăng các câu hỏi linh tinh lên diễn đàn nha bạn , không là bị ăn báo cáo đấy .
a, \(4x^4+81=\left(2x^2\right)^2+9^2=\left(2x^2\right)^2+36x^2+9^2-36x^2\)
\(=\left(2x^2+9\right)^2-\left(6x\right)^2=\left(2x^2-6x+9\right)\left(2x^2+6x+9\right)\)
b, \(64x^4+y^4=\left(8x^2\right)^2+\left(y^2\right)^2=\left(8x^2\right)^2+16x^2y^2+\left(y^2\right)^2-16x^2y^2\)
\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2=\left(8x^2-4xy+y^2\right)\left(8x^2+4xy+y^2\right)\)
6, \(x^2y+xy^2-4x-4y=xy\left(x+y\right)-4\left(x+y\right)=\left(xy-4\right)\left(x+y\right)\)
7, \(10ax-5ay-2x+y=5a\left(2x-y\right)-\left(2x-y\right)=\left(5a-1\right)\left(2x-y\right)\)
8, xem lại đề bạn nhé
9, \(4x^2-y^2+8y-16=4x^2-\left(y^2-8y+16\right)=4x^2-\left(y-4\right)^2\)
\(=\left(2x-y+4\right)\left(2x+y-4\right)\)
Trả lời:
6, x2y + xy2 - 4x - 4y = ( x2y + xy2 ) - ( 4x + 4y ) = xy ( x + y ) - 4 ( x + y ) = ( x + y )( xy - 4 )
7, 10ax - 5ay - 2x + y = ( 10ax - 5ay ) - ( 2x - y ) = 5a ( 2x - y ) - ( 2x - y ) = ( 2x - y )( 5a - 1 )
8, Sửa đề: x3 - 2x2 + 2x - 4 = ( x3 - 2x2 ) + ( 2x - 4 ) = x2 ( x - 2 ) + 2 ( x - 2 ) = ( x - 2 )( x2 + 2 )
9, 4x2 - y2 + 8y - 16 = 4x2 - ( y2 - 8y + 16 ) = 4x2 - ( y - 4 )2 = ( 2x - y + 4 )( 2x + y - 4 )
1, \(x^2\left(x-3\right)-4x+12=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-3\right)\)
2, \(2a\left(x+y\right)-x-y=2a\left(x+y\right)-\left(x+y\right)=\left(2a-1\right)\left(x+y\right)\)
3, \(2x-4+5x^2-10x=2\left(x-2\right)+5x\left(x-2\right)=\left(2+5x\right)\left(x-2\right)\)
4, sửa đề :
\(6x^2-12x-7x+14=6x\left(x-2\right)-7\left(x-2\right)=\left(6x-7\right)\left(x-2\right)\)
5, \(xy-y^2-3x+3y=y\left(x-y\right)-3\left(x-y\right)=\left(y-3\right)\left(x-y\right)\)
a) x2(x-3)-4x+12
=x2(x-3)-4(x-3)
=(x-3)(x2-4)
=(x-3)(x-2)(x+2)
b) 2a(x+y)-x-y
=2a(x+y)-(x+y)
=(x+y)(2a-1)
c) 2x-4+5x2-10x
=2(x-2)+5x(x-2)
=(x-2)(2+5x)
d) 5x2-12x-7x+14
=5x2-19x+14
e) xy-y2-3x+3y
=y(x-y)-3(x-y)
=(x-y)(y-3)
#H
\(3\left(1-4x\right)\left(x-1\right)+4\left(3x-2\right)\left(x+3\right)=-27\)
\(\Leftrightarrow3\left(-1-4x^2+5x\right)+4\left(3x^2+7x-6\right)=-27\)
\(\Leftrightarrow-12x^2+15x-3+12x^2+28x-24=-27\)
\(\Leftrightarrow43x-27=-27\Leftrightarrow x=0\)
\(3\left(1-4x\right)\left(x-1\right)+4\left(3x-2\right)\left(x+3\right)=-27\)
\(\Leftrightarrow\left(3-12x\right)\left(x-1\right)+\left(12x-8\right)\left(x+3\right)=-27\)
\(\Leftrightarrow3x-3-12x^2+12x+12x^2+36x-8x-24+27=0\)
\(\Leftrightarrow43x=0\)
\(\Leftrightarrow x=0\)
#H
Trả lời:
21, ( a + 1 )3 = a3 + 3a2 + 3a + 1
22, ( a + 2 )3 = a3 + 3.a2.2 + 3.a.22 + 23 = a3 + 6a2 + 12a + 8
23, ( x + 1 )3 = x3 + 3x2 + 3x + 1
24, ( x + 2 )3 = x3 + 3.x2.2 + 3.x.22 + 23 = x3 + 6x2 + 12x + 8
25, ( x + 3 )3 = x3 + 3.x2.3 + 3.x.32 + 33 = x3+ 9x2 + 27x + 27
26, ( x + 4 )3 = x3 + 3.x2.4 + 3.x.42 + 43 = x3 + 12x2 + 48x + 64
27, ( 2x + 3y )3 = (2x)3 + 3.(2x)2.3y + 3.2x.(3y)2 + (3y)3 = 8x3 + 36x2y + 54xy2 + 27x3
28, ( 3x + 1 )3 = (3x)3 + 3.(3x)2.1 + 3.3x.12 + 13 = 27x3 + 27x2 + 9x + 1
29, ( 5x + 1 )3 = (5x)3 + 3.(5x)2.1 + 3.5x.12 + 13 = 125x3 + 75x2 + 15x + 1
30, ( 4x + 2y )3 = (4x)3 + 3.(4x)2.2y + 3.4x.(2y)2 + (2y)3 = 64x3 + 96x2y + 48xy2 + 8y3
31, ( a - 1 )3 = a3 - 3a2 + 3a - 1
32, ( a - 2 )3 = a3 - 3.a2.2 + 3.a.22 - 23 = a3 - 6a2 + 12a - 8
33, ( x - 3 )3 = x3 - 3.x2.3 + 3.x.32 - 33 = x3 - 9x2 + 27x - 27
34, ( x - 4 )3 = x3 - 3.x2.4 + 3.x.42 - 43 = x3 - 12x2 + 48x - 64
35, ( x - 5 )3 = x3 - 3.x2.5 + 3.x.52 - 53 = x3 - 15x2 + 75x - 125
36, ( 2x - 3y )3 = (2x)3 - 3.(2x)2.3y + 3.2x.(3y)2 - (3y)3 = 8x3 - 36x2 + 54x - 27x3
37, ( x2 - 2y )3 = (x2)3 - 3.(x2)2.2y + 3.x2.(2y)2 - (2y)3 = x6 - 6x4y + 12x2y2 - 8y3
38, ( 2x2 - 3y )3 = (2x2)3 - 3.(2x2)2.3y + 3.2x2.(3y)2 - (3y)3 = 8x6 - 36x4y + 54x2y2 - 27y3
39, ( 4 - 4y2 )3 = 43 - 3.42.4y2 + 3.4.(4y2)2 - (4y2)3 = 64 - 48y2 + 192y4 - 64y6
40, ( 3x2 - 2y2 )3 = (3x2)3 - 3.(3x2)2.2y2 + 3.3x2.(2y2)2 - (2y2)3 = 27x6 - 54x4y2 + 36x2y4 - 8y6
a, \(a^4+64=\left(a^2\right)^2+8^2=\left(a^2\right)^2+16a^2+8^2-16a^2\)
\(=\left(a^2+8\right)^2-\left(4a\right)^2=\left(a^2-4a+8\right)\left(a^2+4a+8\right)\)
b, \(a^4+4b^2=\left(a^2\right)^2+\left(2b\right)^2=\left(a^2\right)^2+4a^2b+4b^2-4a^2b\)ĐK : b >= 0
\(=\left(a+2b\right)^2-\left(2a\sqrt{b}\right)^2=\left(a+2b-2a\sqrt{b}\right)\left(a+2b+2a\sqrt{b}\right)\)
p/s : mình nghĩ phần b bạn nên để đề là \(a^4+4b^4\)sẽ hợp lí hơn