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Rồi nha :33

(\(x\) - 5)² = 16

(\(x-5\))² = 4²

\(\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)

Vậy \(x\) \(\in\) { 1; 9 }

B. 4^\(x\)  + 33 = 7²

   4\(^x\) + 33 = 49

   4\(^x\)         = 49 - 33

   4\(^x\)        = 16

   4\(^x\)        = 16

  4\(^x\)        = 4²

    \(x\)        = 2

c. 2\(^x\).4 = 128

   2\(^x\)    = 128 : 4

   2\(^x\)    = 32

   2\(^x\)    = 2⁵

   \(x\)      = 5

D, 5\(^x\) . 3 - 75 = 0

    5\(^x\).3      = 75

     5\(^x\)       = 75: 3

    5\(^x\)       = 25

   5\(^x\)        = 5²

     \(x\)       = 2

A) \(\left(x-5\right)^2=16=4^2\Rightarrow\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)

B) \(4^x+33=7^2\Rightarrow4^x=49-33\Rightarrow4^x=16=4^2\Rightarrow x=2\)

C) \(2^x.4=128\Rightarrow2^x=32=2^5\Rightarrow x=5\)

 D) \(5^x.3-75=0\Rightarrow5^x.3=75\Rightarrow5^x=25=5^2\Rightarrow x=2\)

\(1,2\cdot35+2,56:0,8+58\\ =42+3,2+58\\ =103,2\\ \\ \left(23+15:2,5\right):14,5+17\\ =\left(23+6\right):14,5+17\\ =29:14,5+17=2+17\\ =19\)

\(1,2.3,5+2,56:0,8+58=4,2+3,2+58=7,4+58=65,4\)

\(\left\{{}\begin{matrix}x\in B\left(10\right)\\10< x< 60\end{matrix}\right.\\ \Rightarrow x\in\left\{20;30;40;50\right\}\\ \left\{{}\begin{matrix}x⋮2\\0< x< 20\end{matrix}\right.\\ \Rightarrow x\in\left\{2;4;6;8;10;12;14;16;18\right\}\)

a) 4,6,8,10,12

B)5,10,15,20,25

a) 4,6,8,10,12

B)5,10,15,20,25

Ta có x < 19,54 < y

\(\Rightarrow x=19,y=20\)

x = 19 

y = 20

\(xy+2x+2y=-16\)

\(\Rightarrow x\left(y+2\right)+2y+4-4=-16\)

\(\Rightarrow x\left(y+2\right)+2\left(y+2\right)=-12\)

\(\Rightarrow\left(y+2\right)\left(x+2\right)=-12\)

\(\Rightarrow\left(x+2\right);\left(y+2\right)\in B\left(12\right)=\left\{-1;1;-2;2;-3;3;-4;4;-6;6;-12;12\right\}\)

\(\Rightarrow\left(x;y\right)\in=\left\{\left(-3;10\right);\left(-1;-14\right);\left(-4;3\right);\left(0;-8\right);\left(-5;2\right);\left(1;2\right);\left(-6;1\right);\left(2;-5\right);\left(-8;0\right);\left(4;-4\right);\left(-14'-1\right);\left(10;-3\right)\right\}\)

\(\left(x+2\right);\left(y+2\right)\) không phải thuộc B(12) mà nó phải là 2 số nguyên có tích bằng 12 chứ em

`2^x :4=8`

`2^x =8xx4`

`2^x =32`

`2^x =2^5`

`=>x=5`

\(2^x:4=8\\ \Rightarrow2^x=32\\ \Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

1. (Mình đưa nó về thừa số nguyên tố nha, cái nào ko đc thì thôi)

125 = 5³; 27 = 3³; 64 = 2⁶; 1296 = 6⁴; 1024 = 2¹⁰; 2401 = 7⁴; 4³ = 64; 8 = 2³; 25.125 = 3125 = 5⁵.

2.

2ⁿ = 16 =) n = 4.           3ⁿ = 81 =) n = 4.      2^n-1 = 64 =) n = 7.        3ⁿ⁺² = 27.81 =) n = 5.       25.5^n-1 = 625 =) n = 3.

2ⁿ.8 = 128 =) n = 4.     3.5ⁿ = 375 =) n = 3.   (3ⁿ)² = 729 =) n = 3.        81 ≤ 3ⁿ ≤ 729 =) n = 4; 5; 6.

\(125=5^3;27=3^3;1296=36^2=6^4=2^4.3^4;1024=32^2=2^{10};2401=49^2=7^4;4^3=2^6;8=2^3;25.125=5^2.5^3=5^5\)

\(10x+2^2.5=10^2\)

\(10x+4.5=100\)

\(10x+20=100\)

\(10x=100-20\)

\(10x=80\)

\(x=80:10\)

\(x=8\)

x = 8