Lê Trọng Huy
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2024-12-06 20:56:20
a) 0,75 +\(\dfrac{9}{5}\)(1,5-\(\dfrac{2}{3}\))2
= \(\dfrac{75}{100}\)+\(\dfrac{9}{5}\)(\(\dfrac{15}{10}\)-\(\dfrac{2}{3}\))2
=\(\dfrac{3}{4}\)+\(\dfrac{9}{5}\)(\(\dfrac{3}{2}\)-\(\dfrac{2}{3}\))2
=\(\dfrac{3}{4}\)+(\(\dfrac{9}{5}\)*\(\dfrac{3}{2}\)-\(\dfrac{9}{5}\)*\(\dfrac{2}{3}\))2
=\(\dfrac{3}{4}\)+(\(\dfrac{27}{10}\)-\(\dfrac{6}{5}\))2
=\(\dfrac{3}{4}\)+(\(\dfrac{27}{10}\)-\(\dfrac{12}{10}\))2
=\(\dfrac{3}{4}\)+\(\dfrac{9}{4}\)
=\(\dfrac{12}{4}\)