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Phạm Công Đức Minh
Giới thiệu về bản thân
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2025-02-08 22:28:49
the fridge
2025-02-08 21:41:48
3x=5y=4z⇔ 20 x = 12 y = 15 z = 100 5x = 48 4y Áp dụng t/c dãy tỉ số bằng nhau: x 20 = y 12 = z 15 = 5 x 100 = 4 y 48 = 5 x − 4 y + z 100 − 48 + 15 = − 1 67 20 x = 12 y = 15 z = 100 5x = 48 4y = 100−48+15 5x−4y+z = 67 −1 => x = − 1 67 . 20 = − 20 67 ; y = − 1 67 . 12 = − 12 67 ; z = − 1 67 . 15 = − 15 67 x= 67 −1 .20=− 67 20 ;y= 67 −1 .12=− 67 12 ;z= 67 −1 .15=− 67 15