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2025-01-06 16:42:31
B. Đỏ tươi
2024-07-28 09:34:46
125
2024-07-26 08:59:41
5 số chẵn liên tiếp: 2k,2k+2,2k+4,2k+6,2k+8
S=2k+(2k+2)+(2k+4)+(2k+6)+(2k+8)=10k+20
S chia hết cho 10
b) 5 số lẻ liên tiếp: 2k+1,2k+3,2k+5,2k+7,2k+9 có tổng là
S=(2k+1)+(2k+3)+(2k+5)+(2k+7)+(2k+9) = 10k+25 =10k+20+5
=> S:10 dư 5
2024-07-26 08:59:06