Nguyễn Thúy Hằng
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2023-10-03 09:32:28
A=\(\dfrac{1}{3}-\dfrac{8}{15}-\dfrac{1}{7}+\dfrac{2}{3}+\dfrac{-7}{15}+1\dfrac{1}{7}\) B=\(\dfrac{1}{4}\)\(+\dfrac{3}{5}-\dfrac{1}{8}+\dfrac{2}{5}-1\dfrac{1}{4}\)
=\(\left(\dfrac{1}{4}-1\dfrac{1}{4}\right)+\left(\dfrac{3}{5}+\dfrac{2}{5}\right)-\dfrac{1}{8}\)
=-1+1-\(\dfrac{1}{8}\) =\(\dfrac{-1}{8}\)
A=\(\left(\dfrac{1}{3}+\dfrac{2}{3}\right)-\left(\dfrac{8}{15}+\dfrac{7}{15}\right)+\left(1\dfrac{1}{7}-\dfrac{1}{7}\right)\)
=\(\dfrac{3}{3}-\dfrac{15}{15}+1\)
=1-1+1
=1