\(y-y:8=84\\ \\ \Rightarrow y-\left(y.\dfrac{1}{8}\right)=84\\ \\ \Rightarrow y.\left(1-\dfrac{1}{8}\right)=84\\ \\ y.\dfrac{7}{8}=84\\ \\ y=84:\dfrac{7}{8}=96\)

a

\(2⋮x+1\\ \\ x+1\inƯ\left(2\right)=\left\{1;2;-1;-2\right\}\\ \\ \Rightarrow x\in\left\{0;1;-2;-3\right\}\)

Vì \(x\in N\)\(\Rightarrow x\in\left\{0;1\right\}\)

Vậy \(x\in\left\{0;1\right\}\)

a

Số bị chia là: 50x10x5=2500

Đ/S: 2500

C1: \(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\)x\(\dfrac{4}{9}\)=\(\left(\dfrac{3}{9}+\dfrac{2}{9}\right)\text{x}\dfrac{4}{9}\)=\(\dfrac{5}{9}\text{x}\dfrac{4}{9}=\dfrac{20}{81}\)

C2: \(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\)x\(\dfrac{4}{9}\)=\(\dfrac{1}{3}\text{ x}\dfrac{4}{9}+\dfrac{2}{9}\text{ x}\dfrac{4}{9}\)=\(\dfrac{4}{27}+\dfrac{8}{81}=\dfrac{12}{81}+\dfrac{8}{81}=\dfrac{20}{81}\)

Gọi số thứ nhất và số thứ hai lần lượt là A và B

Theo bài ra ta có:  

A+B=68080(1)

A+3B=89668(2)

Lấy (2)-(1) vế theo vế ta có:

  2B=89668-68080=21588

 ⇒ B= 21588:2=10794

 ⇒ A= 68080-10794=57286

Vậy số thứ nhất là 57286; số thứ hai là 10794

B=x⁵-15x⁴+16x³-29x²+13x

B= 14⁵-15.14⁴+16.14³-29.14²+13.14

B=14.14⁴-15.14⁴+16.14³-29.14²+13.14

B=(14-15).14⁴+16.14³-29.14²+13.14

B= (-1).14⁴+16.14³-29.14²+13.14

B= (-1).14⁴+16.14².14-29.14²+13.14

B=(-1).14⁴+224.14²-29.14²+13.14

B= (-1).14⁴+(224-29).14²+13.14

B=(-1).14⁴+195.14²+13.14

B=[(-1).14³].14+195.14.14+13.14

B= (-2744).14+2730.14+13.14

B= 14.[(-2744)+2730+13]

B= 14.(-1)

B= -14

\(\dfrac{3}{46}+\dfrac{4}{23}-\dfrac{1}{115}\\ \\ =\dfrac{3}{46}+\dfrac{8}{46}-\dfrac{1}{115}\\ \\ =\dfrac{11}{46}-\dfrac{1}{115}\\ \\ =\dfrac{53}{230}\)