________, I decided to stop trading with them
A.Despite of the fact that they were the biggest dealer
B.Though being the biggest dealer
C.Being the biggest dealer
D.Even though they were the biggest dealer
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1. I spend an hour doing my homework.
→ It takes me an hour to do my homework.
2(Sửa đề). They spend 6 months building this house.
→ It takes them 6 months to build this house.
Số thứ nhất là:
(24680+2):2=24682:2=12341
Số thứ hai là:
12341-2=12339
\(12+\left(x\times3+5\right):5=16\\ \left(x\times3+5\right):5=16-12\\ \left(x\times3+5\right):5=4\\ x\times3+5=4\times5\\ x\times3+5=20\\ x\times3=20-5\\ x\times3=15\\ x=15:3\\ x=5\)
Vậy: ..
Gọi số cần tìm là x
Theo đề, ta có: \(\dfrac{-9}{5}< \dfrac{-7}{x}< \dfrac{-9}{6}\)
=>\(\dfrac{9}{5}>\dfrac{7}{x}>\dfrac{9}{6}\)
=>\(\dfrac{63}{35}>\dfrac{63}{9x}>\dfrac{63}{42}\)
=>35<9x<42
=>9x=36
=>x=4
Gọi mẫu số của phân số cần tìm là \(x\) ( 0 ≠ \(x\) \(\in\) Z)
\(\dfrac{-9}{5}\) < \(\dfrac{-7}{x}\) < \(\dfrac{-9}{6}\)
⇒ \(\dfrac{-9.\left(-1\right)}{5.}\) > \(\dfrac{-7.\left(-1\right)}{x}\) > \(\dfrac{-9.\left(-1\right)}{6}\) (nhân cả hai vế của bất đẳng thức với một số âm thì bất đẳng thức đổi chiều)
⇒\(\dfrac{9}{5}\) > \(\dfrac{7}{x}\) > \(\dfrac{9}{6}\)
⇒ \(\dfrac{9.7}{5.7}\) > \(\dfrac{7.9}{x.9}\) > \(\dfrac{9.7}{6.7}\)
⇒ \(\dfrac{63}{35}\) > \(\dfrac{63}{9x}\) > \(\dfrac{63}{42}\)
⇒ 35 < 9\(x\) < 42
\(\dfrac{35}{9}\) < \(x\) < \(\dfrac{42}{9}\)
3\(\dfrac{8}{9}\) < \(x\) < 4\(\dfrac{6}{9}\)
Vậy \(x=4\)
1 is
2 are
3 is
4 are
5 are
6 Is - she isn't
7 Are - they aren't
8 Is - he is
9 Are - they aren't
10 Is - it is
1 is 2 are 3 is 4 are 5 are 6 Is 6 she is not a dancer 7 Are 7 they are not 8 Is 9 he is 9 Are 10 Is 10 yes it is
________, I decided to stop trading with them
A.Despite of the fact that they were the biggest dealer
B.Though being the biggest dealer
C.Being the biggest dealer
D.Even though they were the biggest dealer