Mn giúp mk vs ạ .
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Độ dài của chiều cao là:
12:2=6(cm)
=>Diện tích hình bình hành đó là:
12x6=72(cm2)
Đáp số:72 cm2
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\(\dfrac{1}{5}+\dfrac{11}{10}:\sqrt{x}=\dfrac{3}{4}\\ \Rightarrow\dfrac{11}{10}:\sqrt{x}=\dfrac{3}{4}-\dfrac{1}{5}\\ \Rightarrow\dfrac{11}{10}:\sqrt{x}=\dfrac{11}{20}\\ \Rightarrow\sqrt{x}=\dfrac{11}{10}:\dfrac{11}{20}\Rightarrow\sqrt{x}=2\Rightarrow x=4\)
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đề bài có phải như này không em ?
\(3^{x-4.\left(3^2\right)^3}=243\)
< = > \(3^{x-4.\left(3^2\right)^3}=3^5\)
< = > x - 4 . ( 32 )3 = 5
< = > x - 4 . 729 = 5
< = > x - 2916 = 5
< = > x = 2921
\(...\Rightarrow3^{x-4}.3^6=2023\)
\(\Rightarrow3^{x-4+6}=3^5\)
\(\Rightarrow3^{x+2}=3^5\Rightarrow x+2=5\Rightarrow x=3\)
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a) \(...\Rightarrow\left\{{}\begin{matrix}x-2=0\\y+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)
b) \(...\Rightarrow|x-2|=|x+3|\Rightarrow\left[{}\begin{matrix}x-2=x+3\\x-2=-x-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}0x=5\\2x=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x\in\varnothing\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\Rightarrow x=-\dfrac{1}{2}\)
c) \(|x-\dfrac{3}{4}|+|x+\dfrac{5}{4}|=1\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{3}{4}\le0\\x+\dfrac{5}{4}\ge0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x\le\dfrac{3}{4}\\x\ge-\dfrac{5}{4}\end{matrix}\right.\)
\(\Rightarrow-\dfrac{5}{4}\le x\le\dfrac{3}{4}\)
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\(\left(2-x\right)\left(x-2023\right)< 0\)
\(\Rightarrow x< 2\) hay \(x>2023\)
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280 - 9x - x = 80
=> 280 - 10x = 80
=> 280 - 80 - 10x = 80 - 80
=> 200 - 10x = 0
=> 200 -10x + 10x = 10x
=> 200 = 10x
=> x = 10
Vậy x = 10
\(...\Rightarrow280-10x=80\Rightarrow10x=280-80\Rightarrow10x=200\Rightarrow x=200:10=20\)
Hệ số tỉ lệ: k= y:x= 3:(-1)= (-3)