Cho hai số thực x,y. Chứng minh rằng nếu xy+x+y=-1 thì trong hai số x,y có ít nhất một số bằng -1
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thì phân tích thành nhân tử là oke
\(x^2+x+1>0\)
\(\Leftrightarrow x^2+x+\frac{1}{4}+\frac{3}{4}>0\)
\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2+\frac{3}{4}>0\)*đúng*
Ta có:\(x^2+x+1=\left(x^2+x+\frac{1}{4}\right)+\frac{3}{4}=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}\)
Vì\(\left(x+\frac{1}{2}\right)^2\ge0\forall x\in R\Rightarrow\left(x+\frac{1}{2}\right)^2+\frac{3}{4}\ge\frac{3}{4}>0\left(đpcm\right)\)
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\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left[\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75\right)^2\right]:\frac{13}{25}}\)
\(=\frac{\left(\frac{10203}{125}.\frac{3}{16}-\frac{901}{200}\right)+\frac{503}{4}}{\left[\left(\frac{121}{625}.\frac{25}{2}+\frac{353}{100}\right)^2-\frac{121}{16}\right].\frac{25}{13}}\)
\(=\frac{\left(15,3045-\frac{901}{200}\right)+\frac{503}{4}}{\left(\frac{14161}{400}-\frac{121}{16}\right).\frac{25}{13}}\)
\(=\frac{136,5495}{\frac{696}{13}}\)
\(=2,550493534\)
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1)\(\left(-8\right)^2=64\)
2)\(\left(-1,25\right)^2=1,56\)
3) \(3^5=243\)
4) \(2^5:2^3\Leftrightarrow2^{5-3}=2^2\)
5) \(\left(-4\right)^2\times\left(-4\right)=\left(-4\right)^{2+1}=\left(-4\right)^3\)
6) \(\left(\frac{2}{3}\right)^3\times\left(\frac{2}{3}\right)^2=\left(\frac{2}{3}\right)^{3+2}=\left(\frac{2}{3}\right)^5\)
6,1. = 64
2 . = 1,56
3 . =243
4 , = 22 = 4
5 , (-43) = -12
6, = 2/3 5 = 22 / 213
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Tổng số phần bằng nhau là:
4+5=9( phần)
1 phần có số tuổi là:
27 :9=3 (tuổi)
Tuổi em là:
3.4=12(tuổi)
Tuổi chị là:
3.5=15 (tuổi)
Đ/s :Em 12 tuổi
Chị 15 tuổi
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\(\frac{x+2}{5}< \frac{x+2}{3}+\frac{1}{2}\)
\(\Leftrightarrow\frac{6\left(x+2\right)}{30}< \frac{10\left(x+2\right)}{30}+\frac{15}{30}\)
\(\Leftrightarrow\frac{6x+12}{30}< \frac{10x+20}{30}+\frac{15}{30}\)
\(\Leftrightarrow6x+12< 10x+20+15\)
\(\Leftrightarrow6x-10x< 20+15-12\)
\(\Leftrightarrow-4x< 23\)
\(\Leftrightarrow x>-\frac{23}{4}\)
Vậy tập nghiệm của bất phương trình là \(x>-\frac{23}{4}\)
\(\frac{x+2}{4}-x< \frac{1}{3}\)
\(\Leftrightarrow\frac{3\left(x+2\right)}{12}-\frac{12x}{12}< \frac{4}{12}\)
\(\Leftrightarrow\frac{3x+6}{12}-\frac{12x}{12}< \frac{4}{12}\)
\(\Leftrightarrow3x+6-12x< 4\)
\(\Leftrightarrow3x-12x< 4-6\)
\(\Leftrightarrow-9x< -2\)
\(\Leftrightarrow x>\frac{2}{9}\)
Vậy tập nghiệm của bất phương trình là \(x>\frac{2}{9}\)
\(\frac{2x-1}{x+2}< 0\)( ĐKXĐ : \(x\ne-2\))
Xét hai trường hợp
1/ \(\hept{\begin{cases}2x-1< 0\\x+2>0\end{cases}}\Rightarrow\hept{\begin{cases}x< \frac{1}{2}\\x>-2\end{cases}}\Rightarrow-2< x< \frac{1}{2}\)
2/ \(\hept{\begin{cases}2x-1>0\\x+2< 0\end{cases}}\Rightarrow\hept{\begin{cases}x>\frac{1}{2}\\x< -2\end{cases}}\)( loại )
Vậy tập nghiệm của bất phương trình là \(-2< x< \frac{1}{2}\)
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Put the verbs in the brackets in the correct tenses form.
1. Nam looks brown. He was on holiday last week. He (get) ....got...... sunburnt.
2. Getting plenty of a rest is very good. It (help)...........helps...... you to avoid depression.
3. The Japanese (eat) ....eat......... a lot of fish, so they are intelligent.
4. If you wash you hands more, you (have) .....will have..... less chance of catching flu.
5. Eating carrots regularly (help) ...helps...... you see better.
6. It is very hot outside. Please (wear) ......wear..... a sun hat when you go out.
7. Do more exersise and you (feel) ...will feel........ healthier.
8. I don' t want (be) ......to be...... tired tomorrow, so I go to bed early.
9. Nowadays, I don' t feel well. I often (feel)... feel.. sick and weak.
10. People who (smile) ....smile ........ more are happier andthey live longer
II. Put the verbs in brackets in the correct tense form.
1. It is important (eat) .to eat.. well.
2. It (be) ..is. very cold today. You should wear your warm clothes when you (go) .. go . out to prevent cold.
3. Do morning exercise everyday and you'll (feel) ..feel .. better
4. I have a lot of homework to do this evening, so I (not have) .don't have.. time to watch the football match.
5. (Eat) eating ... junk food and inactivity (be)is ... the main causes of obesity.
6. I (have) .have.. a headache and I need to rest more.
7. I (have) ..have. a toothache so I (have to/see) .have to see.. the dentist
8. I have to take medicines because I (be) .am.. sick
9. Japanese (eat) .eat.. more fish instead of meat, so they (stay) .. stay . more healthy.
10. When you ( have) ... a fever, you (should/drink) ... more water and rest more have/should drink
11. A healthy diet (help) ... us feel healthier helps
12. Watching TV much (hurt) ... your eyes hurts
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I. Give the correct form of the word given to complete the sentence.
1. Is she well enough to run one kilometer? | (GOOD) |
2. “Ow! Be careful with that coffee.” - “Look, now I have a burn on my arm” | (BURNING) |
3. Rob has a temperature of 39.50C | (TEMPERATE) |
4. Don’t eat so quickly. You’ll get a toothache | (TEETH) |
5. I have a pain in my back. I’m going to lie down. | (PAINFUL) |
6. That’s a bad cough . Why don’t you have a glass of water? | (COUGHING) |
7. “I have stomachache .” - “Why don’t you telephone the doctor?” | (STOMACH) |
8. My arm hurts after the table tennis match | (HURT) |
9. “I have a headache .” - “That’s because you watch too much TV.” | (HEAD) |
10. Lan was absent from class because of her sickness | (SICK) |
11. I have an appointment with my doctor at 5 p.m. | (APPOINT) |
12. She is still receiving a medical treatment in a hospital. | (MEDICINE) |
13. People fell please when they catch a common cold. | (PLEASE) |
14. She’s allergic to seafood. So when she eats them, she will have stomachache problems. | (ALLERGY) |
15. You should choose foods and drinks carefully to prevent some dangerous diseases. | (CARE) |
16. He continues sneezing because he is catching a flu. | (SNEEZE) |
17. He can reduce his serious depression when he relaxes in time and does exercise regularly. | (DEPRESS) |
18. If you provide yourself with enough vitamins, you will make a better concentrate on your work or study. | (CONCENTRATE) |
19. I got sunburnt during my beach vacation. | (SUNBURN) |
20. Lack of vitamin E can cause skin diseases and tiredness . | (TIRED) |
Ta có : xy + x + y = -1
=> x(y + 1) + y + 1 = -1 + 1
=> (x + 1)(y + 1) = 0
=> \(\orbr{\begin{cases}x+1=0\\y+1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=-1\\y=-1\end{cases}}\)(đpcm)
Vậy nếu xy + x + y = - 1 thì có ít nhất 1 số bằng - 1
xy + x + y = -1
<=> xy + x + y + 1 = 0
<=> x( y + 1 ) + 1( y + 1 ) = 0
<=> ( x + 1 )( y + 1 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}x+1=0\\y+1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-1\\y=-1\end{cases}}\) ( đpcm )