Tính chu vi và diện tích của ABCD.
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a; 576 + 678 + 780 - 475 - 577 - 679
= (576 - 475) + (678 - 577) + (780 - 679)
= 101 + 101 + 101
= 101 x 3
= 303
b; (126 + 32) x (18 - 16 - 2)
= (126 + 32) x ( 2 - 2)
= (126 + 32) x 0
= 0
\(x\) - (10 - \(x\)) = \(x\) - 22
\(x\) - 10 + \(x\) = \(x\) - 22
2\(x\) - 10 = \(x\) - 22
2\(x\) - \(x\) = -22 + 10
\(x\) = - 12
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\times\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(0,25+0,35+0,65+0,75\right)\times\left(1+\dfrac{2}{3}+4+\dfrac{1}{3}\right)\)
\(=2\times6\)
\(=12\)
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\times\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{65}{100}+\dfrac{3}{4}\right)\times\left(\dfrac{15}{9}+\dfrac{13}{3}\right)\)
\(=\left(\dfrac{5}{20}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{15}{20}\right)\times6\)
\(=\left[\left(\dfrac{15}{20}+\dfrac{5}{20}\right)+\left(\dfrac{7}{20}+\dfrac{13}{20}\right)\right]\times6\)
\(=2\times6\)
\(=12\)
Bài 9
a; A = (1 + \(\dfrac{1}{3}\))\(\times\)(1 + \(\dfrac{1}{8}\))\(\times\)(1 + \(\dfrac{1}{15}\))\(\times\)...\(\times\)(1 + \(\dfrac{1}{9999}\))
A = \(\dfrac{3+1}{3}\)\(\times\)\(\dfrac{8+1}{8}\)\(\times\)\(\dfrac{15+1}{15}\)\(\times\)...\(\times\)\(\dfrac{9999+1}{9999}\)
A = \(\dfrac{4}{3}\)\(\times\)\(\dfrac{9}{8}\)\(\times\)\(\dfrac{16}{15}\)\(\times\)...\(\times\)\(\dfrac{10000}{9999}\)
A = \(\dfrac{2\times2\times3\times3\times4\times4\times...\times100\times100}{1\times3\times2\times4\times3\times5\times...\times99\times101}\)
A = \(\dfrac{2\times100}{1\times101}\)
A = \(\dfrac{200}{101}\)
b; B = (1 - \(\dfrac{1}{4}\))\(\times\) (1 - \(\dfrac{1}{9}\)) \(\times\) (1 - \(\dfrac{1}{16}\))\(\times\)...\(\times\)(1 - \(\dfrac{1}{10000}\))
B = \(\dfrac{4-1}{4}\) \(\times\) \(\dfrac{9-1}{9}\) \(\times\) \(\dfrac{16-1}{16}\) \(\times\) \(\dfrac{10000-1}{10000}\)
B = \(\dfrac{3}{4}\)\(\times\) \(\dfrac{8}{9}\)\(\times\)\(\dfrac{15}{16}\)\(\times\)...\(\times\) \(\dfrac{9999}{10000}\)
B = \(\dfrac{1\times3}{2\times2}\)\(\times\)\(\dfrac{2\times4}{3\times3}\)\(\times\)\(\dfrac{3\times5}{4\times4}\)\(\times\)...\(\times\)\(\dfrac{99\times101}{100\times100}\)
B = \(\dfrac{1\times101}{2\times100}\)
B = \(\dfrac{101}{200}\)
\(-35-2x=-19\\\Rightarrow2x=-35-(-19)\\\Rightarrow2x=-35+19\\\Rightarrow2x=-16\\\Rightarrow x=-16:2\\\Rightarrow x=-8\\Vậy:x=-8.\)
−35−2x=−19
⇒2x=−35−(−19)
⇒2x=−35+19
⇒2x=−16
⇒x=−16:2
⇒x=−8
Vậy:x=−8.
Độ dài đoạn BC là:
12 : 4 + 2,3 = 5,3 (cm)
Chu vi của ABCD là:
(5 + 4 + 5,3) x 2 = 28,6 (cm)
Diện tích ABCD là:
9 x 5,3 = 47,4 (cm2)
Đáp số:...
Độ dài BC:
2,3 + 12:4 = 5,3(cm)
Độ dài CD:
5 + 4 = 9 (cm)
Diện tích ABCD:
9 x 5,3= 47,7 (cm2)
Chu vi ABCD:
(5,3 + 9) x 2 = 28,6 (cm)
Đ.số:.....