(3x + 1)³ = 1

(3x + 1)³ = 1³

3x + 1 = 1

3x = 0

x = 0 : 3

x = 0

Cảm ơn em , đã học và hiểu được bài học cũng như đánh giá cao chất lượng bài giảng

cảm ơn vì đã lắng nghe và khẳng định đúng của mình

=5

\(\dfrac{\dfrac{36}{41}:\dfrac{9}{41}}{\dfrac{14}{21}:\dfrac{7}{21}}\) \(\times\) \(\dfrac{2}{5}\)

= \(\dfrac{\dfrac{36}{41}\times\dfrac{41}{9}}{\dfrac{14}{21}\times\dfrac{21}{7}}\) \(\times\) \(\dfrac{2}{5}\)

= \(\dfrac{4}{2}\) \(\times\) \(\dfrac{2}{5}\)

= \(\dfrac{4}{5}\)

\(\dfrac{3\dfrac{1}{3}+\dfrac{1}{5}+2\dfrac{7}{15}}{\left(\dfrac{3}{10}+\dfrac{1}{4}+\dfrac{7}{20}\right).\dfrac{5}{6}}=\dfrac{\dfrac{10}{3}+\dfrac{1}{5}+\dfrac{37}{15}}{\left(\dfrac{6}{20}+\dfrac{5}{20}+\dfrac{7}{20}\right).\dfrac{5}{6}}\)

\(=\dfrac{\dfrac{50}{15}+\dfrac{3}{15}+\dfrac{37}{15}}{\dfrac{18}{20}.\dfrac{5}{6}}=\dfrac{6}{\dfrac{3}{4}}=\dfrac{6.4}{3}=8\)

\(\left(\dfrac{13}{18}\times1,4-2,5\times\dfrac{7}{180}\right):\dfrac{7}{18}\)

\(=\left(\dfrac{13}{18}\times\dfrac{14}{10}-\dfrac{25}{10}\times\dfrac{7}{180}\right)\times\dfrac{18}{7}\)

\(=\left(\dfrac{13}{18}\times\dfrac{7}{5}-\dfrac{5}{2}\times\dfrac{7}{180}\right)\times\dfrac{18}{7}\)

\(=\left(\dfrac{91}{90}-\dfrac{7}{72}\right)\times\dfrac{18}{7}\)

\(=\dfrac{329}{360}\times\dfrac{18}{7}=\dfrac{47}{20}\)

(542 - 541)²⁹³⁸ = 1²⁹³⁸ = 1

(542 + 541)⁰ = 1083⁰ = 1

Vậy : (542  - 541)²⁹³⁸ = (542 + 541)⁰ (đpcm)

=

Ta có:

$3^{39}=3^{3\times33}=(3^{3})^{33}=27^{33}>27^{21}$

Mà $11^{21}<27^{21}=>3^{39}>11^{21}$

3³⁹   = (3¹³)³

11²¹ = (11⁷)³

3¹³  = (3²)⁶.3 = 9⁶.3  < 11⁶. 11 = 11⁷

⇒ 3¹³ < 11⁷ ⇒ (3¹³)³ < (11⁷)³

⇒ 3³⁹ < 11²¹ 

B= {73;74;75:76;77;78;79}

b= {73;74;75:76;77;78;79}

`@` `\text {Ans}`

`\downarrow`

`a)`

`25,7 + 9,48 + 14,3`

`= (25,7 + 14,3) + 9,48`

`=40 + 9,48`

`= 49,48`

`b)`

`8,24 + 3,69 + 2,31`

`= 8,24 + (3,69 + 2,31)`

`= 8,24 + 6`

`= 14,24`

`c)`

`8,65 + 7,6 + 1,35 + 0,4`

`= (8,65 + 1,35) + (7,6 + 0,4)`

`= 10 + 8`

`= 18`

`d)`

`5,92 + 0,44 + 5,56 + 4,08`

`= (5,92 + 4,08) + (0,44 + 5,56)`

`= 10 + 6`

`= 16`

`e)`

`7,5 + 6,5 + 5,5 + 4,5 + 3,5 + 2,5`

`= (7,5 + 2,5) + (6,5 + 3,5) + (5,5 + 4,5)`

`= 10 + 10 + 10`

`= 30`

`7,`

`a)`

Ta có:

\(42,54 > 42,45; 87,65 > 87,56\)

\(\Rightarrow\) \(42,54+87,65>42,56+87,56\) 

`b)`

\(96,38+74,85 = 171,73 \\ 74,38 + 96,85 = 171,23\)

\(\Rightarrow\) \(96,38 + 74,85 = 96,85 + 74,38\)

`c)`

\(8,8 + 6,6 + 4,4 = 8,8 + 11 = 19,8 \\ 9,9 + 5,5 + 7,7 = 23,1\)

`19,8 < 23,1`

\(\Rightarrow\) `8,8 + 6,6 + 4,4 < 9,9 + 5,5 + 7,7`

`@` `\text {Ans}`

`\downarrow`

`3,`

`a)`

\(\dfrac{5}{2}\times\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{5}{6}+\dfrac{1}{4}=\dfrac{13}{12}\)

`b)`

\(\dfrac{6}{5}+\dfrac{3}{5}\div2=\dfrac{6}{5}+\dfrac{3}{10}=\dfrac{3}{2}\)

`c)`

\(\left(\dfrac{6}{15}+\dfrac{3}{15}\right)\times\dfrac{4}{9}=\dfrac{9}{15}\times\dfrac{4}{9}=\dfrac{4}{15}\)

`d)`

\(\dfrac{3}{7}\times\left(\dfrac{9}{11}-\dfrac{2}{11}\right)=\dfrac{3}{7}\times\dfrac{7}{11}=\dfrac{3}{11}\)

`4,`

`a)`

\(\dfrac{3}{7}+\dfrac{4}{9}+\dfrac{4}{7}+\dfrac{5}{9}=\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{7}{7}+\dfrac{9}{9}=1+1=2\)

`b)`

\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)

`c)`

\(\dfrac{1}{15}+\dfrac{4}{15}+\dfrac{5}{18}+\dfrac{7}{18}=\left(\dfrac{1}{15}+\dfrac{4}{15}\right)+\left(\dfrac{5}{18}+\dfrac{7}{18}\right)=\dfrac{1}{3}+\dfrac{2}{3}=1\)

`d)`

\(\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{3}{8}+\dfrac{5}{12}=\left(\dfrac{1}{12}+\dfrac{5}{12}\right)+\left(\dfrac{1}{8}+\dfrac{3}{8}\right)=\dfrac{1}{3}+\dfrac{1}{2}=\dfrac{5}{6}\)