1=2 mũ 0

1=2^x

<=>2⁰=2^x

<=>x=0

c=-1/5-5/4^2:5/8
c=-1/5-25/16:5/8
c=-1/5-5/2
c=-27/10

\(\left(\frac{3}{4}\right)^{2.x}:\left(\frac{2}{5}\right)^{10}=\left(\frac{15}{8}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2.x}=\left(\frac{15}{8}\right)^{10}.\left(\frac{2}{5}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2.x}=\left(\frac{15}{8}.\frac{2}{5}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2.x}=\left(\frac{3}{4}\right)^{10}\)

\(\Rightarrow2.x=10\Rightarrow x=5\)

\(\left(\frac{3}{4}\right)^{2x}\div\left(\frac{2}{5}\right)^{10}=\left(\frac{15}{8}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2x}=\left(\frac{15}{8}\right)^{10}\times\left(\frac{2}{5}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2x}=\left(\frac{15}{8}\times\frac{2}{5}\right)^{10}\)

\(\left(\frac{3}{4}\right)^{2x}=\left(\frac{3}{4}\right)^{10}\)

\(\Rightarrow\)\(2x=10\)

\(\Rightarrow\)\(x=5\)

\(13,7.\left(-2,56\right)+46,31\div0,5-\left[86,3.2,56+53,69\div\left(-0,5\right)\right]\)

\(=\)\(-35,072+92,62-\left[220,928-107,38\right]\)

\(=\)\(57,548-220,928+107,38\)

\(=\)\(-163,38+107,38\)

\(=\)\(-56\)

=-56 nha bạn

HT

3x2+2y2=7xy3x2+2y2=7xy

⇔3x2−7xy+2y2=0⇔3x2−7xy+2y2=0

⇔3x2−6xy−xy+2y2=0⇔3x2−6xy−xy+2y2=0

⇔3x(x−2y)−y(x−2y)=0⇔3x(x−2y)−y(x−2y)=0

⇔(3x−y)(x−2y)=0⇔(3x−y)(x−2y)=0

⇔[3x−y=0x−2y=0⇔[3x−y=0x−2y=0 ⇔[3x=yx=2y⇔[3x=yx=2y

+) TH1 : y=3xy=3x

⇔A=3x+y7y−x+6x−9y2x+y⇔A=3x+y7y−x+6x−9y2x+y

=3x+3x7.3x−x+6x−9.3x2x+3x=3x+3x7.3x−x+6x−9.3x2x+3x

=9x20x+−21x5x=9x20x+−21x5x

=−154=−154

+) TH2 : x=2yx=2y

⇔A=3x+y7y−x+6x−9y2x+y⇔A=3x+y7y−x+6x−9y2x+y

=3.2y+y7y−2y+6.2y−9y2.2y+y=3.2y+y7y−2y+6.2y−9y2.2y+y

=7y5y+3y5y=7y5y+3y5y

=2=2

Vậy...

 4.5 ,31.16

4.5; 3116

MÀ CÁI HÌNH THỨ 2 BÊN GÓC PHẢI LÀ CỦA BÀI 3 NHA