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-3 x - 61 = 5

-3 x        = 5 + 61 

-3 x        = 66

   x         = 66 : -3 

 x          = -22

= 1124056674 nhé

1124056674 anh tự tính được mà :))

mình đang cần gấp

a. Có \(y'=\frac{1}{2\sqrt{x+\sqrt{x^2+1}}}.\left(x+\sqrt{x^2}+1\right)=\frac{1}{2y}.\left(1+\frac{x}{\sqrt{x^2+1}}\right)=\frac{1}{2y}.\left(\frac{x+\sqrt{x^2+1}}{\sqrt{x^2+1}}\right)\)

\(\rightarrow y'=\frac{y^2}{2y\sqrt{x^2+1}}=\frac{y}{2\sqrt{x^2+1}}\)

\(\rightarrow2\sqrt{x^2+1}y'=y\)

b. Theo câu a. có

\(y'=\frac{y}{2\sqrt{x^2+1}}\)

\(\rightarrow y''=\frac{y'.2\sqrt{x^2+1}-y.\left(2\sqrt{x^2+1}\right)'}{4\left(x^2+1\right)}\)

\(\rightarrow4\left(x^2+1\right)y''=2y'\sqrt{x^2+1}-y\frac{2x}{\sqrt{x^2+1}}=y-\frac{4xy}{2\sqrt{x^2+1}}=y-4xy^2'\)

\(\rightarrow4\left(1+x^2\right)y''+4xy'-y=0\)

Câu a: Ta có:

\(y'=\frac{1}{2\sqrt{x+\sqrt{x^2+1}}}\left(x+\sqrt{x^2}+1\right).\)

\(=\frac{1}{2y}\left(1+\frac{x}{\sqrt{x^2+1}}\right)=\frac{1}{2y}\left(\frac{x+\sqrt{x^2+1}}{\sqrt{x^2+1}}\right)\)

\(\rightarrow y'=\frac{y^2}{2y+\sqrt{x^2+1}}=\frac{y}{2\sqrt{x^2+1}}\)

\(\rightarrow2\sqrt{x^2+1}y'=y\)

b) theo câu a, ta có:

\(y'=\frac{y}{2\sqrt{x^2+1}}\)

\(y"=\frac{y'2\sqrt{x^2+1}-y\left(2\sqrt{x^2+1}\right)}{4\left(x^2+1\right)}\)

\(\rightarrow4\left(x^2+1\right)y"=2y'\sqrt{x^2+1}-y\frac{2x}{\sqrt{x^2+1}}\)

\(=y-\frac{4xy}{2\sqrt{x^2+1}}=y-4xy^{2'}\)

\(\rightarrow4\left(1+x^2\right)y"+4xy'-y=0\)

t7fgkfgt8byu