Tìm X :
1 ) 3x - 35 =40 9) 128- 3 (x+4) = 23
2) ( x + 12 ) .25 = 0 10)[ (4x+28).3+55]:5 =35
3) 48: ( x -2 ) = 37 11) 231- ( x- 6 ) = 1339: 13
4) ( x +17 ) :21 -3 = 7 12) (x-15) :5 + 22 =24
5) 218-5. ( x+ 8 ) = 25: 22 13) 42- (2x+32) +12:2 = 6
6) 5x-1- 13= 612 14) 134-2 { 156-6.[ 54-2.(9+6) ] }
7) 3x= 9
8) x2.3= 27
36 giây trước (17:40)
Tìm X :
1 ) 3x - 35 =40
3x = 75
x = 25
2) ( x + 12 ) .25 = 0
Vì ( x + 12 ) .25 = 0
mà \(25\ne0\)
nên x +12 =0
=> x= -12
7) 3x = 32
Vậy x = 2
9) 3(x + 4) = 128 - 23
3(x + 4) = 105
x+4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
Vậy x =31