Đó là hình có đối xứng trục và hình có đối xứng tâm.

->Tính đối xứng có trong hình là đối xứng trục và đối xứng tâm.

a) Chữ cái có trục đối xứng là: A, H, I, M 

b) Các chữ cái có tâm đối xứng là: I và N 

a) Chữ cái có trục đối xứng là: A, H, I, M.

b) Chữ cái có tâm đối xứng là: H, I, N.

Quả dưa hấu nặng:

\(\dfrac{15}{4}:\dfrac{3}{4}=5\left(kg\right)\)

Đáp số: 5kg 

 $\genfrac{}{}{0ex}{}{15}{4}:\genfrac{}{}{0ex}{}{3}{4}=5$ (kg)

Ta có:

\(\dfrac{-2}{3}< \dfrac{-1}{3}< 0< \dfrac{1}{2}\)

Sắp xếp:
\(\dfrac{-2}{3};\dfrac{-1}{3};0;\dfrac{1}{2}\)

−23;−13;0;12

3

−2

​

;

3

−1

​

;0;

2

1

​

.

$\genfrac{}{}{0ex}{}{-2}{3};\genfrac{}{}{0ex}{}{-1}{3};0;\genfrac{}{}{0ex}{}{1}{2}$.

a) \(\dfrac{25}{6}:\dfrac{5}{3}-\left(\dfrac{-1}{4}\right)\)

\(=\dfrac{25}{6}\cdot\dfrac{3}{5}+\dfrac{1}{4}\)

\(=\dfrac{5}{2}+\dfrac{1}{4}\)

\(=\dfrac{10}{4}+\dfrac{1}{4}\)

\(=\dfrac{11}{4}\)

b) \(\dfrac{1}{8}\cdot\dfrac{3}{2}+\dfrac{1}{8}\cdot\dfrac{-1}{2}\)

\(=\dfrac{1}{8}\cdot\left(\dfrac{3}{2}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{8}\cdot\dfrac{2}{2}\)

\(=\dfrac{1}{8}\)

a) $\genfrac{}{}{0ex}{}{25}{6}:\genfrac{}{}{0ex}{}{5}{3}-\left(\genfrac{}{}{0ex}{}{-1}{4}\right)$

$=\genfrac{}{}{0ex}{}{25}{6}\cdot \genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{1}{4}$

$=\genfrac{}{}{0ex}{}{5}{2}+\genfrac{}{}{0ex}{}{1}{4}$

$=\genfrac{}{}{0ex}{}{5.2+1}{4}$

$=\genfrac{}{}{0ex}{}{11}{4}$

b) $\genfrac{}{}{0ex}{}{1}{8}\cdot \genfrac{}{}{0ex}{}{3}{2}+\genfrac{}{}{0ex}{}{1}{8}\cdot \left(-\genfrac{}{}{0ex}{}{1}{2}\right)$

$=\genfrac{}{}{0ex}{}{1}{8}\cdot \left(\genfrac{}{}{0ex}{}{3}{2}-\genfrac{}{}{0ex}{}{1}{2}\right)$

$=\genfrac{}{}{0ex}{}{1}{8}\cdot \genfrac{}{}{0ex}{}{2}{2}$

$=\genfrac{}{}{0ex}{}{1}{8}\cdot 1=\genfrac{}{}{0ex}{}{1}{8}$
 

a) Số đó là:

\(2,6:\dfrac{2}{3}=3,9\)

b) Số đó là: 

\(-\dfrac{1}{2}:1\dfrac{2}{3}=-\dfrac{3}{10}\)

c) Số đó là:

\(-9:\dfrac{5}{8}=-\dfrac{72}{5}\)

d) Số đó là:

\(\dfrac{13}{19}:2\dfrac{1}{6}=\dfrac{6}{19}\)

\(A=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}\)

\(A=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\)

\(A=1-\dfrac{1}{6}\)

\(A=\dfrac{5}{6}\)

_________

\(B=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\)

\(B=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\)

\(B=1-\dfrac{1}{10}\)

\(B=\dfrac{9}{10}\)

___________

\(C=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}\)

\(C=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)

\(C=1-\dfrac{1}{100}\)

\(C=\dfrac{99}{100}\)

\(D=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{110}\)

\(D=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{10\cdot11}\)

\(D=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{10}-\dfrac{1}{11}\)

\(D=1-\dfrac{1}{11}\)

\(D=\dfrac{10}{11}\)

_____________

\(E=\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{19\cdot21}\)

\(E=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{19}-\dfrac{1}{21}\)

\(E=1-\dfrac{1}{21}\)

\(E=\dfrac{20}{21}\)

___________

\(F=\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{27\cdot30}\)

\(F=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{27}-\dfrac{1}{30}\)

\(F=1-\dfrac{1}{30}\)

\(F=\dfrac{29}{30}\)

= -1/2 + 3/5 - 1/9 + 1/27 - 7/18 + 4/35 + 2/7

= (-1/2 - 1/9 - 7/18) + (3/5 + 4/35 + 2/7)  + 1/27

= (-9/18 - 2/18 - 7/18) + (21/35 + 4/35 + 10/35) + 1/27

= -18/18 + 35/35 + 1/27

= -1 + 1 + 1/27

= 1/27