II -Tìm x biết:
(2x – 2) . 2024 = 0 | (5x – 5) . 2 = 60 |
15 : (6 – x) = 5 | 3(3x – 1) = 42 |
[(10 – x).2 +5]:3 – 2 = 3 | 121 – 21(x – 1) = 121 |
134: (x - 3) = 35 + 160 :5 | 697:[(15.x + 364) :x] = 17 |
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22 . 47 + 2 . 38 . 11 + 15 .22
= 22 . 47 + 22 . 38 + 15 .22
= 22 . ( 47 + 38 + 15 )
= 22 . 100
= 2200
3 . 75 . 8 + 2 . 11 . 12 + 6 . 15 . 4
= ( 3 . 8 ) . 75 + ( 2 . 12 ) . 11 + ( 6 . 4 ) .15
= 24 . 75 + 24 . 11 + 24 . 15
= 24 . ( 75 + 11 + 15 )
= 24 . 101
= 2424
3) 37 . 24 + 37 . 76 + 63 . 79 + 63 . 21;
= 37 . ( 24 + 76 ) + 63 . ( 79 + 21 )
= 37 . 100 + 63 . 100
= 3700 + 6300
= 10 000
4) 41 . 75 + 41 . 26 + 59 . 37 + 59 . 74
= 41 . ( 75 + 26 ) + 59 . ( 37 + 74 )
= 41 . 101 + 59 . 111
= 4141 + 6549
= 10690
5) 68 – 28 : 2
= 68 - 14
= 54
6) 31 . 86 + 31 .10 + 31 . 5
= 31 . ( 86 + 10 + 5 )
= 31 . 101
= 3131
7) 17 . 85 + 17 . 15 – 120
= 17 . ( 85 + 15 ) - 120
= 17 . 100 - 120
= 1700 - 120
= 1580
#HOCTOT
(20 - x) : 3 + 40 = 46
(20 - x) : 3 = 46 - 40
(20 - x) : 3 = 6
(20 - x) = 6 x 3
(20 - x) = 18
x = 20 - 18
x = 2
`59^2 - 59 . 19`
`= 3481 - 59 . 19`
`= 59 . 59 - 59 . 19`
`= 59 . (59 - 19)`
`= 59 . 40`
`= 2360`
a) 100:{250:[450−(4.53−25.4)]}100:{250:[450−(4.53−25.4)]}
=100:{250:[450−(4.125−25.4)]}=100:{250:[450−(4.125−25.4)]}
=100:{250:[450−(500−100)]}=100:{250:[450−(500−100)]}
=100:[250:(450−400)]=100:[250:(450−400)]
=100:(250:50)=100:(250:50)
=100:5=100:5
=20=20
b) 4(18−15)−(5−3).324(18−15)−(5−3).32
=4.3−2.32=4.3−2.32
=4.3−2.9=4.3−2.9
=12−18=12−18
=−6=−6
Mình đang cần gấp
\(\left(2x-2\right).2024=0\)
\(\left(2x-2\right)=0\div2024\)
\(2x-2=0\)
\(2x=0+2\)
\(2x=2\)
\(x=1\)
\(15\div\left(6-x\right)=5\)
\(\left(6-x\right)=15\div5\)
\(6-x=3\)
\(x=6-3\)
\(x=3\)
\(\left[\left(10-x\right).2+5\right]\div3-2=3\)
\(\left[\left(10-x\right).2+5\right]\div3=3+2\)
\(\left[\left(10-x\right).2+5\right]\div3=5\)
\(\left(10-x\right).2+5=5.3\)
\(\left(10-x\right).2+5=15\)
\(\left(10-x\right).2=15-5\)
\(\left(10-x\right).2=10\)
\(\left(10-x\right)=10\div2\)
\(10-x=5\)
\(x=10-5\)
\(x=5\)
\(134\div\left(x-3\right)=35+160\div5\)
\(134\div\left(x-3\right)=35+32\)
\(134\div\left(x-3\right)=67\)
\(\left(x-3\right)=134\div67\)
\(x-3=2\)
\(x=2+3\)
\(x=5\)