= 2060

k ha!!

.

Trả lời :

12 + 30 + 2018 = 2060

_Hnay lak ngày SN Kim Taehyung V ( My Idol)

# Nhạt

\(a^2-2a+b^2+4b+4c^2-4c+6=0\)'

\(\left(a^2-2a+1\right)+\left(b^2+4b+4\right)+\left(4c^2-4c+1\right)=0\)

\(\left(a-1\right)^2+\left(b+2\right)^2+\left(2c-1\right)^2=0\)

b tự làm nốt nhé~

\(M=\left(x+3\right)\left(x^2-3x+9\right)-\left(x^3+54-x\right)\)

\(M=x^3+3^3-x^3-54+x\)

\(M=x+27-54\)

\(M=x+27-54\)

\(M=7-27\)

\(M=-20\)

24 + 2 + 2004

= 26 + 2004

= 2030

Hk tốt 

>.<

  24 + 2 + 2004

= 26 + 2004

= 2030

girl 2k7

Mình nghĩ y^2 chứ nhỉ :[

khhong bạn ạ. Đề là y^3 , đề y^2 mik giải đc rồi nhé

eeeeee

\(2;A=\left(\frac{x}{x^2-4}+\frac{1}{x+2}-\frac{2}{x-2}\right):\left(\frac{1-x}{x+2}\right)\)

\(ĐKXĐ:\hept{\begin{cases}x^2-4\ne0\\1-x\ne0\end{cases}}\Rightarrow\hept{\begin{cases}x\ne\pm2\\x\ne1\end{cases}}\)

\(a,A=\left(\frac{x}{\left(x-2\right)\left(x+2\right)}+\frac{x-2}{\left(x+2\right)\left(x-2\right)}-\frac{2\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}\right).\frac{x+2}{1-x}\)

\(A=\left(\frac{x+x-2-2x-4}{\left(x+2\right)\left(x-2\right)}\right).\frac{x+2}{1-x}\)

\(A=\frac{-6}{\left(x+2\right)\left(x-2\right)}.\frac{x+2}{1-x}=\frac{-6}{\left(x-2\right)\left(1-x\right)}\)

b, Khi x = -4

\(A=\frac{-6}{\left(-4-2\right)\left(1+4\right)}=\frac{-6}{-6.5}=\frac{1}{5}\)

cảm ơn bạn