2x=2048
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a) `2/3` của 14 là:
\(\dfrac{2}{3}\times14=\dfrac{28}{3}\)
b) `5/4` của 451 là:
\(\dfrac{5}{4}\times451=\dfrac{2255}{4}\)
c) Đổi: \(1\dfrac{1}{3}=\dfrac{4}{3}\)
`4/3` của 60:
\(\dfrac{4}{3}\times60=80\)
d) 23% của 50 là:
\(23\%\times50=11,5\)
\(\left(1+2+3+...+2017\right)\times\left(1717\times18-1818\times17\right)\\ =\left(1+2+3+...+2017\right)\times\left(17\times101\times18-18\times101\times17\right)\\ =\left(1+2+3+...+2017\right)\times0\\ =0\)
`(-1/27) . 3/7 + 5/9 . (-3/7)`
`1/27 . (-3/7) + 5/9 . (-3/7)`
`(1/27 + 5/9) . (-3/7)`
`16/27 . (-3/7)`
`-16/63`
(\(\dfrac{3}{7}\)+(\(-\dfrac{3}{7}\))). \(\left(-\dfrac{1}{27}\right)\).\(\dfrac{5}{9}\)
= 0.\(\left(-\dfrac{1}{27}\right)\).\(\dfrac{5}{9}\)
=0
\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}\)
=\(\left(0,5+0,4\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{5}{7}-\dfrac{4}{35}\right)\)
= \(0,9+\left(\dfrac{2}{6}+\dfrac{1}{6}\right)+\left(\dfrac{25}{35}-\dfrac{4}{35}\right)\)
= \(0,9+\dfrac{3}{6}+\dfrac{21}{35}\)
= `0,9 +0,5 + 0,6`
= `2`
\(\dfrac{2}{3}-\left[-\dfrac{7}{4}-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)
\(=\dfrac{2}{3}+\dfrac{7}{4}+\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\)
\(=\dfrac{8}{12}+\dfrac{21}{12}+\dfrac{6}{12}+\dfrac{3}{8}\)
\(=\dfrac{35}{12}+\dfrac{3}{8}=\dfrac{70}{24}+\dfrac{9}{24}=\dfrac{79}{24}\)
\(\dfrac{2}{3}-\left[\dfrac{-7}{4}-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\\ =\dfrac{2}{3}-\left[\dfrac{-7}{4}-\left(\dfrac{4}{8}+\dfrac{3}{8}\right)\right]\\ =\dfrac{2}{3}-\left(\dfrac{-7}{4}-\dfrac{7}{8}\right)\\ =\dfrac{2}{3}-\left(\dfrac{-14}{8}-\dfrac{7}{8}\right)\\ =\dfrac{2}{3}+\dfrac{21}{8}\\ =\dfrac{16}{24}+\dfrac{63}{24}\\ =\dfrac{79}{24}\)
k+10<25
=>k<15
x\(\in\)N*
=>x>0
=>4k+2>0
=>k>-0,5
=>-0,5<k<15
mà k nguyên
nên k\(\in\left\{0;1;2;3;...;14\right\}\)
=>\(x\in\left\{2;6;10;...;58\right\}\)
2x = 4048
=> x = 4048 : 2
=> x = 2024
Vậy x = 2024
x=1024