a) -(x-6)=18

-x+6=18

-x=12

a) -18-(x-6)=0

          x-6=(-18)-0

          x-6=-18

          x   = (-18)+6

          x   = -12

b) 29-(10+29)=x-(27-9)

   29-39        = x-18

     -10         =x-18

     x-18=-10

     x    = (-10)+18

     x    = 8

Học tốt

Túi nhẹ nhất nặng 12/7kg=1,71428...kg

Nhẹ nhất là túi xoài

a) 7 - ( 18 + x ) = - 15

18 + x = 7+ 15

18 + x = 22

x = 22 - 18

x = 4

vậy x= 4

Trl:

a) \(7-\left(18+x\right)=-15\)

\(\Rightarrow\left(18+x\right)=7-\left(-15\right)\)

\(\Rightarrow\left(18+x\right)=7+15\)

\(\Rightarrow\left(18+x\right)=22\)

\(\Rightarrow x=22-18\)

\(\Rightarrow x=4\)

b) \(\left(x-17\right)-\left(-3\right)=0\)

\(\Rightarrow\left(x-17\right)+3=0\)

\(\Rightarrow\left(x-17\right)=0-3\)

\(\Rightarrow\left(x-17\right)=-3\)

\(\Rightarrow x=-3+17\)

\(\Rightarrow x=14\)

a) 15-(x-5)=-1

         x-5= 15-(-1)=15+1

         x-5= 16

         x   = 16+5

         x=21

b) -39-x=-3-16

    -39-x= -19

         x=(-39)-(-19)=(-39)+19

         x=-20

Học tốt bạn nhé

Trl:

a) \(15-\left(x-5\right)=-1\)

\(\Rightarrow\left(x-5\right)=15-\left(-1\right)\)

\(\Rightarrow\left(x-5\right)=15+1\)

\(\Rightarrow\left(x-5\right)=16\)

\(\Rightarrow x=16+5\)

\(\Rightarrow x=21\)

b) \(-39-x=-3-16\)

\(\Rightarrow-39-x=-19\)

\(\Rightarrow x=-39-\left(-19\right)\)

\(\Rightarrow x=-39+19\)

\(\Rightarrow x=-20\)

a,5

b,súng ngắm

c,=crang là gì đó

you chs ff  ak

Trl:

Ko chắc đâu

a) \(20-x=8-\left(26-10\right)\)

\(\Rightarrow20-x=8-16\)

\(\Rightarrow20-x=-8\)

\(\Rightarrow20-\left(-8\right)\)

\(\Rightarrow x=28\)

b) \(x-13=-13-14\)

\(\Rightarrow x-13=-27\)

\(\Rightarrow x=-27+13\)

\(\Rightarrow x=-14\)

a)20-x=8-(26-10)

   20-x=-8

        x=20-(-8)

        x=28

  Vậy x=28

b)x-13=-13-14

   x-13=-27

   x     =-14

Vậy x=-14

HỌC TỐT!

\(n^2-2n+7=\left(n^2-n\right)-\left(n-1\right)+6=n\left(n-1\right)-\left(n-1\right)+6\)

\(=\left(n-1\right)\left(n-1\right)+6=\left(n-1\right)^2+6\)

Vì \(\left(n-1\right)^2⋮n-1\)\(\Rightarrow\)Để \(n^2-2n+7⋮n-1\)thì \(6⋮n-1\)

\(\Rightarrow n-1\inƯ\left(6\right)=\left\{\pm1;\pm2;\pm3;\pm6\right\}\)

\(\Rightarrow n\in\left\{-5;-2;-1;0;2;3;4;7\right\}\)

Vậy \(x\in\left\{-5;-2;-1;0;2;3;4;7\right\}\)

Ta co: 3+3^3+3^5+...+3^1991 = (3+3^3+3^5)+...+(3^1987+1989+1991) =3.(1+3^2+3^4)+...+3^1987.(1+3^2+3^4) =3.91+...+3^1987.91 =(3+..+3^1987).91=(3+...+3^1987).13.7 chia het cho 13 3+3^3+3^5+...+3^1991 =(3+3^3+3^5+3^7)+...+(3^1985+3^1987+3^1989+3^1991) =3(1+3^2+3^4+3^6)+...+3^1985.(1+3^2+3^4+3^6) =3.820+...+3^1985.820=(3+...+3^1985).820=(3+....+3^1985).41.20 chia het cho 41

WHY CHO 3^223 CƠ MÀ