làm xong đầu tiên chọn luôn

20001²⁰⁰¹³ :(-20001)²⁰⁰¹² = 20001²⁰⁰¹³ : 20001²⁰⁰¹²  = 2

a)(x-1/2)^3=1/27

=>(x-1/2)^3=(1/3)^3

=>x-1/2=1/3

=>x=5/6

b)(x+1/2)^2=4/25

=>(x+1/2)^2=(2/5)^2

=>x+1/2=2/5

=>.x=-1/10

a, \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)

\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)

\(\Rightarrow x-\frac{1}{2}=\frac{1}{3}\)

\(\Rightarrow x=\frac{5}{6}\)

Vậy \(x=\frac{5}{6}\)

b, \(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)

\(\Rightarrow\left(x+\frac{1}{2}\right)^2=\left(\frac{2}{5}\right)^2\)

\(\Rightarrow x+\frac{1}{2}=\frac{2}{5}\)

\(\Rightarrow x=\frac{-1}{10}\)

Vậy \(x=\frac{-1}{10}\)

\(2^x+2^{x+4}=544\)   

\(2^x\left(1+2^4\right)=544\)

\(2^x\left(1+16\right)=544\)   

\(2^x\cdot17=544\)   

\(2^x=544:17\)   

\(2^x=32\)   

\(2^x=2^5\)   

\(\Rightarrow x=5\)

2^x+2^x.2⁴=544

(2^x)².16=544

2^2x.16=544

2^2x=34

2x=34

x=34:2

x=17

a) ADTCDTSGNTC

\(\frac{a}{2}=\frac{b}{3}=\frac{c}{4}=\frac{a+b-c}{2+3-4}=\frac{5}{1}=5\)

\(\Rightarrow a=10\)

\(b=15\)

\(c=20\)

b) ADTCDTSBNTC

\(\frac{x}{-7}=\frac{y}{4}=\frac{2x}{-14}=\frac{3y}{12}=\frac{2x-3y}{-14-12}=\frac{-78}{-26}=3\)

\(\Rightarrow x=-21\)

\(y=12\)

c) ADTCDTSBNTC

\(\frac{a}{2}=\frac{b}{3}=\frac{2b}{6}=\frac{c}{4}=\frac{3c}{12}=\frac{a+2b-3c}{2+6-12}=\frac{-20}{-4}=5\)

\(\Rightarrow a=10\)

\(b=15\)

\(c=20\)

k mk nhe

cailoon nha

ai giải giúp với ạ

\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{12}\)

\(\frac{y}{4}=\frac{2}{5}\Rightarrow\frac{y}{12}=\frac{2}{15}\)

\(\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{2}{15}\)

\(ADTCDTSBNTC\)

\(\frac{x}{8}=\frac{y}{12}=\frac{2}{15}=\frac{x+y-2}{8+12-15}=\frac{10}{5}=2\)

\(\Rightarrow x=16\)

\(y=24\)