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đợi mấy phút giải ra đây

a) \(\frac{8}{24}+\frac{-12}{24}=\frac{-4}{24}\) \(=-\frac{1}{6}\)

b )  \(-\frac{12}{18}+\frac{8}{40}=\)\(-\frac{2}{3}+\frac{1}{5}\)\(=-\frac{10}{15}+\frac{3}{15}=-\frac{7}{15}\)

c)  \(\frac{12}{36}+\frac{-24}{21}=\frac{1}{3}-\frac{-8}{7}=\)\(\frac{7}{21}-\frac{24}{21}\)\(=\frac{-17}{21}\)

d ) \(\frac{-10}{16}+\frac{42}{-35}=\frac{-10}{16}+\frac{-42}{35}=\frac{-5}{8}-\frac{6}{5}\)\(=\frac{-25}{40}-\frac{48}{40}=\frac{-73}{40}\)

MSC:6

Quy đồng:

\(\frac{-5}{6}=\frac{-5}{6}\)\(;\) \(-6=\frac{\left(-6\right)\cdot6}{1\cdot6}=\frac{-36}{6}\)

x = (5*a+7)

       _____

       (a+1)

65 nha

\(\frac{-5}{8}+\frac{7}{2}+\frac{-23}{8}< \frac{-1}{3}+1+\frac{7}{3}\)

\(\Rightarrow0< x< \frac{-5}{3}\)

Vì \(x\in N\Rightarrow x=1\)

1/5 MŨ 2 X 1/4 + 1/20

= 1/25 X 1/4 +1/20
= 1/100 +1/20
= 3/50

\(\left(\frac{1}{5}\right)^2\cdot\frac{1}{4}+\frac{1}{20}=\frac{1}{25}\cdot\frac{1}{4}+\frac{1}{20}=\frac{1}{100}+\frac{5}{100}=\frac{6}{100}=\frac{3}{50}\)

\(\frac{57}{89}=\frac{89-32}{89}=1-\frac{32}{89}\)

\(\frac{31}{64}=\frac{64-33}{64}=1-\frac{33}{64}\)

Có \(\frac{32}{89}< \frac{33}{64}\)suy ra \(\frac{57}{89}>\frac{31}{64}\).