1+1 bằng mấy tick 3 lần
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A. 1997 + 24 = (1997 + 3) + (24 - 3)
= 2000 + 21
= 2021
B. 29 + 1994 = (29 - 6) + (1994 + 6)
= 23 + 2000
= 2023
\(\sqrt{x-3}-2\ne0\)
\(\sqrt{x-3}\ne2\)
\(x\ne7\left(1\right)\)
\(\sqrt{x-3}\ge0\)
\(x\ge3\left(2\right)\)
\(\left(1\right);\left(2\right)< =>x\ge3;x\ne7\)
\(15.a,\sqrt{3}\left(\sqrt{4}+2\sqrt{9}\right)\frac{\sqrt{3}}{2}-\sqrt{150}\)
\(\left(2+2.3\right)\frac{3}{2}-\sqrt{150}\)
\(12-\sqrt{150}\)
\(6\left(2-\sqrt{25}\right)=6\left(-3\right)=-18\)
\(b,\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right).\sqrt{7}+2\sqrt{21}\)
\(\sqrt{196}-\sqrt{84}-7+2\sqrt{21}\)
\(14-\sqrt{21}\left(\sqrt{4}+2\right)-7\)
\(7-\sqrt{21}.4\)
\(7-\sqrt{84}\)
\(c,\left(1+\sqrt{2}-\sqrt{3}\right)\left(1+\sqrt{2}+\sqrt{3}\right)\)
\(1+\sqrt{2}-\sqrt{3}+\sqrt{2}+2-\sqrt{6}+\sqrt{3}+\sqrt{6}-3\)
\(=2\sqrt{2}\)
\(d,\sqrt{3}\left(\sqrt{2}-\sqrt{3}\right)^2-\sqrt{3}+\sqrt{2}\)
\(\sqrt{3}\left(2-\sqrt{6}+3\right)-\sqrt{3}+\sqrt{2}\)
\(\sqrt{3}\left(5-\sqrt{6}-1\right)+\sqrt{2}\)
\(\sqrt{3}\left(4-\sqrt{6}\right)+\sqrt{2}\)
\(4\sqrt{3}-\sqrt{18}+\sqrt{2}\)
\(\sqrt{2}\left(2\sqrt{3}-3+1\right)\)
\(\sqrt{2}\left(2\sqrt{3}-2\right)\)
\(2\sqrt{6}-\sqrt{6}=\sqrt{6}\)
bằng 2
= 2 nha!!