đề bài là gì

Đề bài là so sánh 2 phân số sau ạ !

a) \(2^4=16\)

\(\RightarrowƯ\left(16\right)=\left\{1;2;4;8;16\right\}\)

b) \(3^2\cdot5=45\)

\(\RightarrowƯ\left(45\right)=\left\{1;3;5;15;45\right\}\)

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\(3^5\cdot4^5=\left(3\cdot4\right)^5=12^5\)

12⁵

`3^4.3`

`=3.3.3.3.3`

`=3^5`

`=243`

3 mũ 5 nha bn

\(1^1\)=1

\(^{10^5}\)=10 x 10 x 10 x10 x 10 = 100000

1 x 100000 = 100000

thank you nhoa mãi iu

`(1/2+1)(1/3+1)(1/4+1)....(1/99+1)`

`=(1/1+2/2)(1/3+3/3)(1/4+4/4)....(1/99+99/99)`

`=3/2 . 4/3 . 5/4 ....... 100/99`

`=` \(\dfrac{3.4.5....100}{2.3.4.....99}\)

`=100/2`

`=50`

=3/2.4/3.5/4...........100/99

=3.4.5..........100/2.3.4............99

=100/2=50

\(\dfrac{2}{1\cdot4}+\dfrac{2}{4\cdot7}+...+\dfrac{2}{97\cdot100}\)

\(=2\cdot\left(\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+...+\dfrac{1}{97\cdot100}\right)\)

\(=\dfrac{2}{3}\left(\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{97\cdot100}\right)\)

\(=\dfrac{2}{3}\left(\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{97}-\dfrac{1}{100}\right)\)

\(=\dfrac{2}{3}\left(\dfrac{1}{1}-\dfrac{1}{100}\right)\)

\(=\dfrac{2}{3}\cdot\dfrac{99}{100}=\dfrac{33}{50}\)

= 7/33 + 3/19.( 17/11-25/11)

= 7/33+ 3/19. (-8/11)

= 7/33+  ( -24/209)

= 61/627