Thay x=-2 và y=8 vào y=ax², ta được:

4a=8

hay a=2

= 3005 g

= 500 năm

= Đề sai.

xin lỗi bạn

Khi x=0 thì y=2022

Khi y=0 thì x+2022=0

hay x=-2022

Tính ra giúp e đc ko ạ?

a/ 10/9 - X = 5/7

X = 10/9 - 5/7

X = 25/63.

b/ 8/3 : X = 3/4

X = 8/3 : 3/4 

X = 32/9. 

10/9 - x = 5/7

x = 10/9 - 5/7 = 25/63

8/3 / x = 3/4

x = 8/3 / 3/4 = 32/9

a.\(A=\left(\dfrac{x-\sqrt{x}+2}{x-\sqrt{x}-2}-\dfrac{x}{x-2\sqrt{x}}\right):\dfrac{1-\sqrt{x}}{2-\sqrt{x}}\)

\(A=\left(\dfrac{x-\sqrt{x}+2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}-\dfrac{x}{\sqrt{x}\left(\sqrt{x}-2\right)}\right):\dfrac{1-\sqrt{x}}{2-\sqrt{x}}\)

\(A=\dfrac{\sqrt{x}\left(x-\sqrt{x}+2\right)-x\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}.\dfrac{2-\sqrt{x}}{1-\sqrt{x}}\)

\(A=\dfrac{x\sqrt{x}-x+2\sqrt{x}-x\sqrt{x}-x}{\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}.\dfrac{2-\sqrt{x}}{1-\sqrt{x}}\)

\(A=\dfrac{2\sqrt{x}-2x}{\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}.\dfrac{2-\sqrt{x}}{1-\sqrt{x}}\)

\(A=\dfrac{2\sqrt{x}\left(1-\sqrt{x}\right)\left(2-\sqrt{x}\right)}{\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)\left(1-\sqrt{x}\right)}\)

\(A=\dfrac{-2}{\sqrt{x}+1}\)

\(A=-2\)

\(\Leftrightarrow-\dfrac{2}{\sqrt{x}+1}=-2\)

\(\Leftrightarrow-2=-2\sqrt{x}-2\)

\(\Leftrightarrow-2\sqrt{x}=0\)

\(\Leftrightarrow x=0\left(tm\right)\)

Vậy \(S=\left\{0\right\}\)

nghiệm xấu quá pạn:<

= [ 50 x ( 76 - 24 + 22)] x 2 

= 50 x 74 x 2

= (50 x 2) x 74

= 100 x 74

= 7400.

7400

\(A=\sqrt{50}-\sqrt{18}+\sqrt{\left(2\sqrt{2}-3\right)^2}\)

\(A=5\sqrt{2}-3\sqrt{2}+\left|2\sqrt{2}-3\right|\)

\(A=2\sqrt{2}+3-2\sqrt{2}\) ( vì \(2\sqrt{2}-3< 0\) )

\(A=3\)

\(A=\sqrt{50-\sqrt{18+\sqrt[]{\left(2\sqrt[]{2-3}\right)}^2}}\)

A=3

Tính AC hẻ:v?

Xét Δ ABC vuông tại A, có :

\(BC^2=AB^2+AC^2\) (Py - ta - go)

=> \(5^2=3^2+AC^2\)

=> \(AC^2=16\)

=> AC = 4 (cm)

Đề thiếu á bạn:<

\(\dfrac{3}{6};\dfrac{2}{5};\dfrac{6}{10};\dfrac{3}{7}\)

\(\dfrac{3}{6},\dfrac{2}{5},\dfrac{6}{10},\dfrac{3}{7}.\)