a) \(\left|x\right|=0\Rightarrow x=0\)

b) \(\left|x\right|=\frac{1}{5}\Rightarrow x=\pm\frac{1}{5}\)

c) +d) (2 phần này đề giống nhau à bạn?) \(\left|x\right|=1,357\Rightarrow x=\pm1,357\) 

e) \(\left|x\right|=3\frac{1}{4}\Rightarrow x=\pm3\frac{1}{4}\)

g) \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}\)

f) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=\frac{-1}{2}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}-\frac{3}{4}\\x=\frac{-1}{2}-\frac{3}{4}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{-5}{4}\end{cases}}\)

\(a,|x|=0\)

=>  x   =  0

\(b,|x|=\frac{1}{5}\)

=>   \(\orbr{\begin{cases}x=\frac{1}{5}\\x=-\frac{1}{5}\end{cases}}\)

\(c,|x|=1,357\)

=>  \(\orbr{\begin{cases}x=1,357\\x=-1,357\end{cases}}\)

\(d,|x|=1\cdot357\)

=>  \(\orbr{\begin{cases}x=357\\x=-357\end{cases}}\)

\(e,|x|=3\)

=>  \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)

\(|x|=\frac{1}{4}\)

=>   \(\orbr{\begin{cases}x=\frac{1}{4}\\x=-\frac{1}{4}\end{cases}}\)

\(g,|x+\frac{4}{15}|-|-3,75|=-|-2,15|\)

=>   \(|x+\frac{4}{15}|-3,75=-2,15\)

=>  \(|x+\frac{4}{15}|=1,6=\frac{8}{5}\)

=>  \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{24}{15}\\x+\frac{4}{15}=-\frac{24}{15}\end{cases}}\)       =>     \(\orbr{\begin{cases}x=\frac{20}{15}=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)

\(f,|x+\frac{3}{4}|-\frac{1}{2}=0\)

=>   \(|x+\frac{3}{4}|=\frac{1}{2}\)

=>   \(\orbr{\begin{cases}x+\frac{3}{4}=\frac{2}{4}\\x+\frac{3}{4}=-\frac{2}{4}\end{cases}}\)

=>      \(\orbr{\begin{cases}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{cases}}\)

giải hộ mình với

\(a,\frac{4^2\cdot4^3}{2^{10}}=\frac{\left(2^2\right)^5}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)

\(b,\frac{2^7\cdot9^3}{6^5\cdot8^2}=\frac{2^7\cdot3^9}{2^5\cdot3^5\cdot2^6}=\frac{2^7\cdot3^9}{2^{11}\cdot3^5}=\frac{3^4}{2^4}=\left(\frac{3}{2}\right)^4\)

\(=\left(10x2\right)^8\)

\(=20^8\)

\(=\left(10.2\right)^8=20^8\)