(-2,5)^2= ?

Trả lời:

(-2,5)²=(-2,5).(-2,5)=6,25

Giải :

( - 2,5 )² = \(\left(\frac{-5}{2}\right)^2\)

\(=\frac{\left(-5\right)^2}{2^2}=\frac{25}{4}\)

\(( 1 - 2x )^4 = \frac{1}{128}\)

\(\Rightarrow1-2x=\frac{1}{\sqrt[4]{128}}=\frac{-1}{\sqrt[4]{128}}\)

\(\Rightarrow\orbr{\begin{cases}1-2x=\frac{1}{\sqrt[4]{128}}\\1-2x=\frac{-1}{\sqrt[4]{128}}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x=1-\frac{1}{\sqrt[4]{128}}\\2x=1-\frac{-1}{\sqrt[4]{128}}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{1-\frac{1}{\sqrt[4]{128}}}{2}\\x=\frac{1-\frac{-1}{\sqrt[4]{128}}}{2}\end{cases}}\)

\(\left(1-2x\right)^4=\frac{1}{128}\)

\(\Leftrightarrow1-2x=\frac{\sqrt[4]{2}}{4}\)

\(\Leftrightarrow2x=\frac{1-\sqrt[4]{2}}{4}\)

hay \(x=\frac{1-\sqrt[4]{2}}{8}\)

 số 1/128 ko tach dc mũ 4 

\(\frac{a-1}{2}=\frac{b-2}{3}=\frac{c-3}{4}=\frac{2b-4}{6}=\frac{3c-9}{12}\)

\(=\frac{a-1+2b-4+3c-9}{2+6+12}\)

\(=\frac{a+2b+3c-14}{20}\)

\(=\frac{14-14}{20}=0\)

\(\frac{a-1}{2}=0\Rightarrow a=1\)

\(\frac{b-2}{3}=0\Rightarrow b=2\)

\(\frac{c-3}{4}=0\Rightarrow c=3\)

Vậy a = 1; b = 2; c = 3.

\(\frac{a-1}{2}=\frac{b-2}{3}=\frac{c-3}{4}\)\(=\frac{2b-4}{6}\)\(=\frac{3c-9}{12}\)

\(=\)\(\frac{a-1+2b-4+3c-9}{2+6+12}\)

\(=\)\(\frac{a+2b+3c-14}{20}=\)\(\frac{14-14}{20}20\)

\(\frac{a-1}{2}=0\Rightarrow a=1\)

\(\frac{b-2}{3}=0\Rightarrow b=2\)

\(\frac{c-3}{4}=0\Rightarrow c=3\)

x+y=10

x,y thuộc {1;2;3;4;5;6;7;8;9}