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\(3\times\left(x-2\right)+9=30\)
\(3\times\left(x-2\right)=30-9\)
\(3\times\left(x-2\right)=21\)
\(x-2=7\)
\(x=9\)
\(\left(x+9\right)+\left(x-2\right)+\left(x+7\right)+\left(x-4\right)+\left(x+5\right)+\left(x-6\right)+\left(x+3\right)+\left(x-8\right)+\left(x+1\right)=95\)
\(x+9+x-2+x+7+x-4+x+5+x-6+x+3+x-8+x+1=95\)
\(\left(x\times9\right)+\left(9-2+7-4+5-6+3-8+1\right)=95\)
\(x\times9+5=95\)
\(x\times9=95-5\)
\(x\times9=90\)
\(x=90:9\)
\(x=10\)
(x + 9) + (x - 2) + (x + 7) + (x - 4) + (x + 5) + (x - 6) + (x + 3) + (x - 8) + (x + 1) = 95
x + 9 + x - 2 + x + 7 + x - 4 + x + 5 + x - 6 + x + 3 + x - 8 + x + 1
(x + x + x + x + x + x + x + x + x) + (9 - 8 + 7 - 6 + 5 - 4 + 3 - 2 + 1) = 95
9 × x + 5 = 95
9 × x = 95 - 5
9 × x = 90
x = 90 : 9
x = 10
\(\dfrac{x}{2013}\) - \(\dfrac{1}{10}\) - \(\dfrac{1}{15}\) - \(\dfrac{1}{21}\)-...-\(\dfrac{1}{120}\) = \(\dfrac{5}{8}\)
(\(\dfrac{x}{2013}\) - \(\dfrac{1}{10}\) - \(\dfrac{1}{15}\) - \(\dfrac{1}{21}\)-...- \(\dfrac{1}{120}\))\(\times\)\(\dfrac{1}{2}\) = \(\dfrac{5}{8}\)\(\times\)\(\dfrac{1}{2}\)
\(\dfrac{x}{4026}\) - \(\dfrac{1}{20}-\dfrac{1}{30}-\dfrac{1}{42}-...-\dfrac{1}{240}\) = \(\dfrac{5}{16}\)
\(\dfrac{x}{4026}\) - (\(\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+...+\dfrac{1}{240}\)) = \(\dfrac{5}{16}\)
\(\dfrac{x}{4026}\) - (\(\dfrac{1}{4\times5}\)+ \(\dfrac{1}{5\times6}\)+\(\dfrac{1}{6\times7}\)+...+\(\dfrac{1}{15\times16}\)) = \(\dfrac{5}{16}\)
\(\dfrac{x}{4026}\) - (\(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{6}\) + \(\dfrac{1}{6}\) - \(\dfrac{1}{7}\)+...+ \(\dfrac{1}{15}\) - \(\dfrac{1}{16}\)) = \(\dfrac{5}{16}\)
\(\dfrac{x}{4026}\) - (\(\dfrac{1}{4}\) - \(\dfrac{1}{16}\)) = \(\dfrac{5}{16}\)
\(\dfrac{x}{4026}\) = \(\dfrac{5}{16}\) +( \(\dfrac{1}{4}\) - \(\dfrac{1}{16}\))
\(\dfrac{x}{4026}\) = \(\dfrac{5}{16}\) + \(\dfrac{3}{16}\)
\(\dfrac{x}{4026}\) = \(\dfrac{8}{16}\)
\(\dfrac{x}{4026}\) = \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{1}{2}\) \(\times\) 4026
\(x\) = 2013
a) 53,2 : (X - 3,5) + 45,8 = 99
53,2 : (X - 3,5) = 99 - 45,8
53,2 : (X - 3,5) = 53,2
X - 3,5 = 53,2 : 53,2
X - 3,5 = 1
X = 1 + 3,5
X = 4,5
--------------------
b) 71 + 65 × 4 = (X + 140)/X + 260
(X + 140)/X + 260 = 331
(X + 140)/X = 331 - 260
(X + 140)/X = 71
X + 140 = 71 × X
71 × X - X = 140
70 × X = 140
X = 140 : 2
X = 70
1) (455 - x : 2 × 6) : 5 = 31
455 - x : 2 × 6 = 31 × 5
455 - x : 2 × 6 = 155
x : 2 × 6 = 455 - 155
x : 2 × 6 = 300
x : 2 = 300 : 6
x : 2 = 50
x = 50 × 2
x = 100
--------------------
2) (674 - 23 × 23) : x × 2 = 58
(674 - 529) : x × 2 = 58
145 : x × 2 = 58
145 : x = 58 : 2
145 : x = 29
x = 145 : 29
x = 5
--------------------
3) 235 - x × 5 + 365 = x × 35
(235 + 365) - x × 5 = x × 35
600 - x × 5 = x × 35
x × 35 + x × 5 = 600
x × 40 = 600
x = 600 : 40
x = 15
--------------------
4) 674 + x : 3 × 18 - x × 46 = 541
674 + x × 1/3 × 18 - x × 46 = 541
x × 46 - x × 6 = 674 - 541
x × 40 = 133
x = 133 : 40
x = 3,325
--------------------
5) (x × 24) : (x × 4) = 132 - (x × 7)
6 = 132 - (x × 7)
x × 7 = 132 - 6
x × 7 = 126
x = 126 : 7
x = 18
(1/15 + 1/35 + 1/63) × x = 1
(21/315 + 9/315 + 5/315) × x = 1
35/315 × x = 1
1/9 × x = 1
x = 1 : 1/9
x = 9
` @ L I N H `
(1/15 + 1/35 + 1/63) × x = 1
(21/315 + 9/315 + 5/315) × x = 1
35/315 × x = 1
1/9 × x = 1
x = 1 : 1/9
x = 9
tổng độ dài 2 đáy:
2x25=50(cm)
độ dài chiều cao hình thang
100:50=2(cm)
tổng đọ dài 2 đáy sau khi tăng:
50 + 15=65(cm)
diện tích hình thang sau khi tăng
65 x 2=130(cm2)
Đáp số:130cm2
Chúc bạn học giỏi.Thi đỗ Trần Đăng Ninh.
Diện tích hình thang tăng thêm là bao nhiêu thế em?
vì gọi a/b là phân số cần tìm
nếu cộng 2 ta có : (a+2)/b= 1 =>a+2= b
nếu cộng 3 ta có a/(b+3) =1/2 => 2a=b+3
thay b vào 2a=b+3 =>a= 7
thay a vào => b= 11