Cho số M = 2016+p1.p2...pn(với p1,p2,...,pm là n số đầu tiên n>2012). Hỏi M có phải số chính phương?
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1, Ta có :
\(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)
\(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)
\(x+\frac{3}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{3}{5}\)
\(x=\frac{15}{10}-\frac{6}{10}\)
\(x=\frac{9}{10}\)
Vậy x = \(\frac{9}{10}\)
2, Ta có :
\(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)
\(\frac{3}{4}\div x=-\frac{5}{6}\)
\(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)
\(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)
\(x=-\frac{9}{10}\)
Vậy x = \(-\frac{9}{10}\)
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Giải :
- ( 1999 + 313 ) – 1999 = 1999 – 1999 + 313 = 313
( 1435 + 213 ) – 13 = 1435 + ( 213 – 13 ) = 1435 + 200 = 1635
- 2034 – ( 34 + 1560 ) = ( 2034 – 34 ) – 1560 = 2000 – 1560 = 440
1972 – ( 364 + 972 ) = 1972 – 972 – 368 = 1000 – 368 = 632
c. 364 – ( 364 – 111 ) = 364 – 364 + 111 = 111
249 – ( 75-51 ) = ( 249 + 51 ) – 75 = 300 – 75 = 225
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Make the sentenes with the given words:
1. Our classmates/ be/ to/ beaches/ Nha trang/ many/ times.
-> Our classmates have been to many beaches Trang many times
2. Instead/ keys, we/ will/ have/ special/ cards/ start/ the/ engine/ the car.
-> Instead of using keys, we will have special cards to start the engine of the car
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\(\left(75\%+\frac{1}{2}\right)\text{ : }\left|-1\frac{1}{2}\right|-\frac{5}{27}\cdot1,8\cdot2012^0\)
\(=\left(\frac{3}{4}+\frac{1}{2}\right):\left|-\frac{3}{2}\right|-\frac{5}{27}\cdot\frac{9}{5}\)
\(=\frac{5}{4}\text{ : }\frac{3}{2}-\frac{1}{3}\)
\(=\frac{5}{6}-\frac{1}{3}\)
\(=\frac{1}{2}\)
\(\left(75\%+\frac{1}{2}\right)-\left|-1\frac{1}{2}\right|-\frac{5}{27}\cdot1,8\cdot2012^0\)
\(=\left(\frac{75}{100}+\frac{1}{2}\right)-\left|-\frac{3}{2}\right|-\frac{5}{27}\cdot\frac{9}{5}\cdot1\)
\(=\left(\frac{3}{4}+\frac{1}{2}\right)-\frac{3}{2}-\frac{5}{27}\cdot\frac{9}{5}\)
\(=\left(\frac{3}{4}+\frac{2}{4}\right)-\frac{3}{2}\cdot\frac{1}{3}\)
\(=\frac{5}{4}-\frac{1}{2}=\frac{5}{4}-\frac{2}{4}=\frac{3}{4}\)
Ez mà :)))
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\(\frac{7}{5}.\left(\frac{-11}{8}+\frac{-9}{8}\right)+\frac{9}{2}\)
\(\frac{7}{5}.\left(\frac{-5}{2}\right)+\frac{9}{2}\)
\(\frac{-7}{2}+\frac{9}{2}\)
=1
\(\frac{7}{5}.\frac{-11}{8}+\frac{7}{5}.\frac{9}{-8}+4\frac{1}{2}\)
=\(\frac{7}{5}.\left(\frac{-11}{8}+\frac{-9}{8}\right)+\frac{9}{2}\)
=\(\frac{7}{5}.\frac{-20}{8}+\frac{9}{2}\)
=\(\frac{-140}{40}+\frac{9}{2}\)
=\(\frac{-7}{2}+\frac{9}{2}=\frac{2}{2}=1\)
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Ta có: p1, p2, p3,...pn là n số nguyên tố đầu tiên
=> p1.p2.p3....pn chia hết cho 3 và không chia hết cho 9
Đặt p1.p2...pn =3k, k không chia hết cho 3
=> M=2016+p1.p2.p3...pn=9.224+3k=3(3.224+k)
Giả sử M là số chính phương khi đó M chia hết cho 9
=> 3.224+k chia hết cho 3 => k chia hết cho 3 ( vô lí vì k ko chia hết cho 3)
Vậy M ko là số chính phương