Tớ đang cần gấp aa.

Ta có: 

\(\overline{abcd}+\overline{abcd}=3576\)

\(\Rightarrow2\cdot\overline{abcd}=3576\)

\(\Rightarrow\overline{abcd}=\dfrac{3576}{2}=1788\)

\(\Rightarrow a=1;b=7;c=8;d=8\)

#\(Toru\)

=10 x abc + d + abc = 3576

= 11 x abc + d = 3576

= 3576 : 11 = abc ( dư d) 

Ta có : 357 : 11 = 325 ( dư 1 )

abc= 325 , d = 1

BBạn tra gg nh

\(\dfrac{2^{39}+2^{35}}{2^{33}\cdot4}\)

\(=\dfrac{2^{35}\cdot\left(2^4+1\right)}{2^{33}\cdot2^2}\)

\(=\dfrac{2^{35}\cdot\left(16+1\right)}{2^{35}}\)

\(=17\)

\(---\)

\(\dfrac{4^{17}+4^3}{4^{16}+4^2}\)

\(=\dfrac{4^3\cdot\left(4^{14}+1\right)}{4^2\cdot\left(4^{14}+1\right)}\)

\(=4\)

#\(Toru\)

giúp mình với mình đang vội

\(3\cdot5^2+15\cdot2^2-1^2\cdot48\\ =2^2\cdot18-48\\ =72-48\\ =24\)

x=3

\(3^2x-4-x^0=8\)

\(\Rightarrow9\cdot x-4-1=8\)

\(\Rightarrow9\cdot x-5=8\)

\(\Rightarrow9\cdot x=8+5\)

\(\Rightarrow9\cdot x=13\)

\(\Rightarrow x=\dfrac{13}{9}\)

`(3x-1)^2=25`

`=>3x-1=5` hoặc `3x-1=-5`

`=>x=2` hoặc `x=-4/3`

x:3x-1=5^2

x:3-1=5

x:3=5+1

x:3=6

x=6.3

x=18

2904

\(53\times51+4+53\times49+91+53\)

\(=53\times\left(51+49\right)+\left(4+53+91\right)\)

\(=53\times100+148\)

\(=5300+148\)

\(=5448\)

`#3107.101107`

\(\text{53 x 51 + 4 + 53 x 49 + 91 + 53}\)

\(=53\times\left(51+49\right)+\left(4+91+53\right)\\ =53\times100+148\\ =5300+148\\ =5448\)

=135,384

\(1+\left(x-1\right)^2+\left(x-1\right)^4+...+\left(x-1\right)^{2020}=\dfrac{17^{2022}-1}{\left(x-1\right)^2-1}\left(đk:x>2\right)\)

đặt 

\(A=1+\left(x-1\right)^2+\left(x-1\right)^4+...+\left(x-1\right)^{2020}\)

\(\left(x-1\right)^2A=\left(x-1\right)^2+\left(x-1\right)^4+\left(x-1\right)^6+...+\left(x-1\right)^{2022}\)

\(\left(x-1\right)^2A-A=\left[\left(x-1\right)^2+\left(x-1\right)^4+\left(x-1\right)^6+...+\left(x-1\right)^{2022}\right]-\left[1+\left(x-1\right)^2+\left(x-1\right)^4+...+\left(x-1\right)^{2020}\right]\)

\(\left[\left(x-1\right)^2-1\right]A=\left(x-1\right)^{2022}-1\)

\(A=\dfrac{\left(x-1\right)^{2022}-1}{\left(x-1\right)^2-1}\)

\(=>\dfrac{\left(x-1\right)^{2022}-1}{\left(x-1\right)^2-1}=\dfrac{17^{2022}-1}{\left(x-1\right)^2-1}\\ =>\left(x-1\right)^{2022}-1=17^{2022}-1\\ =>\left(x-1\right)^{2022}=17^{2022}\\ =>x-1=17\\ =>x=18\left(tm\right)\)