ai làm được tui cho 5 sao

N là số âm hoặc dương 

         3n + 1 ⋮ n + 2 (n  ≠ -2)

3.(n + 2) - 5 ⋮ n + 2

                5 ⋮  n + 2

n + 2 \(\in\) Ư(5) =  {-5; -1; 1; 5}

n         \(\in\) { -7; -3; -1; 3}

3x-2=8

3x=8+2

3x=10

x=10:3

x=10/3

2000000000-1000000000

x=30 (chắc thế)

i: \(\dfrac{25}{-125}=\dfrac{25:\left(-25\right)}{\left(-125\right):\left(-25\right)}=\dfrac{-1}{5}\)

j: \(\dfrac{-28}{-35}=\dfrac{\left(-28\right):\left(-7\right)}{\left(-35\right):\left(-7\right)}=\dfrac{4}{5}\)

k: \(\dfrac{-15}{123}=\dfrac{-15:3}{123:3}=\dfrac{-5}{41}\)

l: \(\dfrac{18}{-153}=\dfrac{18:\left(-9\right)}{\left(-153\right):\left(-9\right)}=\dfrac{-2}{17}\)

m: \(\dfrac{16}{-64}=\dfrac{-16}{64}=\dfrac{-16:16}{64:16}=\dfrac{-1}{4}\)

n: \(\dfrac{-25}{-75}=\dfrac{25}{75}=\dfrac{25:25}{75:25}=\dfrac{1}{3}\)

o: \(\dfrac{-14}{56}=\dfrac{-14:14}{56:14}=\dfrac{-1}{4}\)

p: \(-\dfrac{48}{96}=-\dfrac{48:48}{96:48}=-\dfrac{1}{2}\)

Cái này phải có hình kèm theo em ạ!

a: \(\dfrac{36}{-48}=\dfrac{-36}{48}=\dfrac{-36:12}{48:12}=\dfrac{-3}{4}\)

b: \(\dfrac{-15}{50}=\dfrac{-15:5}{50:5}=\dfrac{-3}{10}\)

c: \(\dfrac{-18}{-81}=\dfrac{-18:\left(-9\right)}{-81:\left(-9\right)}=\dfrac{2}{9}\)

d: \(\dfrac{145}{215}=\dfrac{145:5}{215:5}=\dfrac{29}{43}\)

e: \(\dfrac{5}{10}=\dfrac{5:5}{10:5}=\dfrac{1}{2}\)

f: \(\dfrac{-18}{-27}=\dfrac{-18:\left(-9\right)}{-27:\left(-9\right)}=\dfrac{2}{3}\)

g: \(\dfrac{-42}{105}=\dfrac{-42:21}{105:21}=\dfrac{-2}{5}\)

h: \(\dfrac{75}{-135}=\dfrac{75:\left(-15\right)}{\left(-135\right):\left(-15\right)}=-\dfrac{5}{9}\)

a: \(\dfrac{125}{1000}=\dfrac{125:125}{1000:125}=\dfrac{1}{8}\)

b: \(\dfrac{25}{50}=\dfrac{25:25}{50:25}=\dfrac{1}{2}\)

c: \(\dfrac{16}{32}=\dfrac{16:16}{32:16}=\dfrac{1}{2}\)

d: \(\dfrac{15}{45}=\dfrac{15:15}{45:15}=\dfrac{1}{3}\)

e: \(\dfrac{20}{100}=\dfrac{20:20}{100:20}=\dfrac{1}{5}\)

f: \(\dfrac{4}{16}=\dfrac{4:4}{16:4}=\dfrac{1}{4}\)

g: \(\dfrac{5}{50}=\dfrac{5:5}{50:5}=\dfrac{1}{10}\)

h: \(\dfrac{2}{18}=\dfrac{2:2}{18:2}=\dfrac{1}{9}\)

i: \(\dfrac{3}{12}=\dfrac{3:3}{12:3}=\dfrac{1}{4}\)

j: \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)

k: \(\dfrac{2}{10}=\dfrac{2:2}{10:2}=\dfrac{1}{5}\)

l: \(\dfrac{3}{24}=\dfrac{3:3}{24:3}=\dfrac{1}{8}\)

m: \(\dfrac{4}{28}=\dfrac{4:4}{28:4}=\dfrac{1}{7}\)

l: \(\dfrac{7}{49}=\dfrac{7:7}{49:7}=\dfrac{1}{7}\)

o: \(\dfrac{18}{36}=\dfrac{18:18}{36:18}=\dfrac{1}{2}\)

p: \(\dfrac{45}{60}=\dfrac{45:15}{60:15}=\dfrac{3}{4}\)

x: \(1=1;4=2^2\)

=>\(ƯCLN\left(1;4\right)=1\)

=>1/4 là phân số tối giản

y: \(2=2;10=2\cdot5\)

=>\(ƯCLN\left(2;10\right)=2\)

=>\(ƯCLN\left(-2;10\right)=2>1\)

=>\(\dfrac{-2}{10}\) không là phân số tối giản

z: \(6=2\cdot3;9=3^2\)

=>\(ƯCLN\left(6;9\right)=3\)

=>\(ƯCLN\left(6;-9\right)=3>1\)

=>\(\dfrac{6}{-9}\) không là phân số tối giản

w: \(13=13;14=2\cdot7\)

=>\(ƯCLN\left(13;14\right)=1\)

=>\(ƯCLN\left(13;-14\right)=1\)

=>\(\dfrac{13}{-14}\) là phân số tối giản