a) \(A=x^3-3x^2+3x+1012\)

\(A=x^3-3\cdot x^2\cdot1+3\cdot x\cdot1^2-1+1013\)

\(A=\left(x-1\right)^3+1013\)

Thay x=11 vào A ta có:

\(A=\left(11-1\right)^3+1013=10^3+1013=1000+1013=2013\)

b) \(B=x^3-6x^2+12x-108\)

\(B=x^3-3\cdot2\cdot x^2+3\cdot2^2\cdot x-8-100\)

\(B=\left(x-2\right)^3-100\)

Thay x=12 vào B ta có:

\(B=\left(12-2\right)^3-100=10^3-100=1000-100=900\)

c) \(C=x^3+6x^2y+12xy^2+8y^3\)

\(C=x^3+3\cdot2y\cdot x^2+3\cdot\left(2y\right)^2\cdot x+\left(2y\right)^3\)

\(C=\left(x+2y\right)^3\)

Thay x=-2y vào C ta được:

\(C=\left(-2y+2y\right)^3=0^3=0\)

d) \(D=x^3+9x^2+27x+2027\)

\(D=x^3+3\cdot3\cdot x^2+3\cdot3^2\cdot x+27+2000\)

\(D=\left(x+3\right)^3+2000\)

Thay x=-23 vào D ta có:

\(D=\left(-23+3\right)^3+2000=\left(-20\right)^3+2000=-8000+2000=-6000\)

Hiệu số phần bằng nhau:

\(5-2=3\) (phần)

Độ dài đường chéo thứ nhất là:

\(234:3\times2=156\left(m\right)\)

Độ dài đường chéo thứ hai:

\(156+234=390\left(m\right)\)

Diện tích của mảnh đất:

\(\left(390\times156\right):2=30420\left(m^2\right)\)

Đáp số: ...

\(56-\left(x+2\right)=22\)

\(x+2=56-22\)

\(x+2=34\)

\(x=34-2\)

\(x=32\)

Bạn Hoa có tất cả số quyển sách là:

\(14+5=19\) (quyển sách)

Đáp số: 19 quyển sách

\(1000\times1000-a:5\)

\(=1000000-a:5\)

\(=1000000-a\cdot\dfrac{1}{5}\)

\(=\dfrac{1}{5}\cdot\left(5000000-a\right)\)

a) \(y\times15+y\times13=560\times45\)

\(y\times\left(15+13\right)=25200\)

\(y\times28=25200\)

\(y=25200:28\)

\(y=900\)

b) \(y\times345-y\times44-y=123600\)

\(y\times\left(345-44-1\right)=123600\)

\(y\times300=123600\)

\(y=123600:300\)

\(y=412\)

a) \(980+y:94=8245\)

\(y:94=7265\)

\(y=7265\times94\)

\(y=682910\)

b) \(45\times y\times36=3240\)

\(45\times y=3240:36\)

\(45\times y=90\)

\(y=90:45\)

\(y=2\)

c) \(3865-y+875=1000\)

\(3865-y=125\)

\(y=3865-125\)

\(y=3740\)

d) \(4788:126\times y=1596\)

\(126\times y=4788:1596\)

\(126\times y=3\)

\(y=\dfrac{3}{126}\)

\(y=\dfrac{1}{42}\)

e) \(24624:y:9=76\)

\(y:9=24624:76\)

\(y:9=324\)

\(y=324\times9\)

\(y=2916\)

a) \(\dfrac{3}{5}\) của 105kg = 63 kg

345 giây = 5 phút 45 giây

980087 dag = 980 tạ 87 dag

b) \(\dfrac{3}{4}ha\dfrac{1}{5}dam^2\) = 7520 \(m^2\)

40087 \(dm^2\) = 400 \(m^2\) 8700 \(cm^2\)

\(\dfrac{2}{3}\) giờ 29 phút = 4140 giây

a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)

\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)

\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)

\(\dfrac{1}{2}:y=\dfrac{125}{36}\)

\(y=\dfrac{1}{2}:\dfrac{125}{36}\)

\(y=\dfrac{18}{125}\)

b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)

\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)

\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)

\(y=\dfrac{1}{3}:\dfrac{1}{2}\)

\(y=\dfrac{2}{3}\)

c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)

\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)

\(y:\dfrac{1}{3}=\dfrac{7}{12}\)

\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)

\(y=\dfrac{7}{36}\)

a) \(\dfrac{4}{5}\cdot\dfrac{5}{8}:\dfrac{4}{5}=\left(\dfrac{4}{5}:\dfrac{4}{5}\right)\cdot\dfrac{5}{8}=1\cdot\dfrac{5}{8}=\dfrac{5}{8}\)

b) \(\dfrac{5}{6}+\left(\dfrac{1}{2}:\dfrac{3}{2}+\dfrac{4}{5}\right)=\dfrac{5}{6}+\left(\dfrac{1}{2}\cdot\dfrac{2}{3}+\dfrac{4}{5}\right)=\dfrac{5}{6}+\left(\dfrac{1}{3}+\dfrac{4}{5}\right)=\dfrac{17}{15}+\dfrac{5}{6}=\dfrac{59}{30}\)