\(3x-5=2x-1\\ 3x-2x=-1+5\\ x=4\)

Sửa lại câu 2.

2³.5²-[131-(23-2³)² ]

=200-(131-15²)

=200-(-94)

=294

\(\left(2x-3\right)^2=\dfrac{4}{25}\\ \Rightarrow\left(2x-3\right)^2=\left(\pm\dfrac{2}{5}\right)^2\\ \Rightarrow\left[{}\begin{matrix}2x-3=\dfrac{2}{5}\\2x-3=-\dfrac{2}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=\dfrac{17}{5}\\2x=\dfrac{13}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{17}{10}\\x=\dfrac{13}{10}\end{matrix}\right.\)

2³.5²=2.2.2.5.5=(2.5).(2.5).2=10.10.2=200

2³.5²-[131-(23-2³)² ]=2.2.2.5.5-[131-(23-8)² ]=(2.5).(2.5).2-(131-15² )=10.10.2.(-94)=-9400.2=-18800

\(\dfrac{3}{5}=\dfrac{3\times2}{5\times2}=\dfrac{6}{10}\\ \dfrac{4}{5}=\dfrac{4\times2}{5\times2}=\dfrac{8}{10}\\ 6< 7< 8=>\dfrac{3}{5}< \dfrac{7}{10}< \dfrac{4}{5}\)

\(-\dfrac{5}{6}+3x=\dfrac{2}{3}-\dfrac{1}{2}x\\ \Rightarrow3x+\dfrac{1}{2}x=\dfrac{2}{3}+\dfrac{5}{6}\\ \Rightarrow\left(3+\dfrac{1}{2}\right)x=\dfrac{3}{2}\\ \Rightarrow\dfrac{7}{2}x=\dfrac{3}{2}\\ \Rightarrow x=\dfrac{3}{2}:\dfrac{7}{2}\\ \Rightarrow x=\dfrac{3}{7}\)

Anh POP POP sai rồi. \(11-1^2\ne10^2\)

\(695-\left[200+\left(11-1^2\right)\right]\\ =695-\left[200+\left(11-1\right)\right]\\ =695-\left(200+10\right)\\ =695-210\\ =485\)

\(\left(25\times32\right):8=25\times32:8=25\times\left(32:8\right)=25\times4=100\\ 24\times11+6\times86\times4+72\\ =24\times11+24\times86+24\times3\\ =24\times\left(11+86+3\right)\\ =24\times100=2400\\ 36\times5+9\times79\times4+72\times8\\ =36\times5+36\times79+36\times16\\ =36\times\left(5+79+16\right)\\ =36\times100=3600\\ \left(56\times125\right):7=56\times125:7=\left(56:7\right)\times125=8\times125=1000\)

\(\dfrac{7}{6}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{5}{6}-\dfrac{3}{4}\\ =\left(\dfrac{7}{6}+\dfrac{5}{6}-1\right)\times\dfrac{3}{4}\\ =1\times\dfrac{3}{4}=\dfrac{3}{4}\\ \dfrac{6\times7\times15\times8}{4\times21\times10\times3}\\ =\dfrac{2\times3\times7\times5\times3\times4\times2}{4\times7\times3\times5\times2\times3}\\ =2\)