\(110-3\times\left(8+x\right)=1\)

\(3\times\left(8+x\right)=110-1\)

\(3\times\left(8+x\right)=109\)

\(8+x=\dfrac{109}{3}\)

\(x=\dfrac{109}{3}-8\)

\(x=\dfrac{85}{3}\)

Chúc bạn học tốt

\(\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}\)

\(=\dfrac{67}{9}+\dfrac{51}{11}-\dfrac{31}{9}\)

\(=\dfrac{67}{9}-\dfrac{31}{9}+\dfrac{51}{11}\)

\(=4+\dfrac{51}{11}\)

\(=\dfrac{95}{11}\)

Chúc bạn học tốt

I will be on the beach.

a) \(\dfrac{7}{5}.\dfrac{8}{19}+\dfrac{7}{5}.\dfrac{12}{19}-\dfrac{7}{5}.\dfrac{1}{19}\)

\(=\dfrac{7}{5}.\left(\dfrac{8}{19}+\dfrac{12}{19}-\dfrac{1}{19}\right)\)

\(=\dfrac{7}{5}.1\)

\(=\dfrac{7}{5}\)

b) \(\dfrac{-3}{5}.\dfrac{5}{7}+\dfrac{-3}{5}.\dfrac{3}{7}+\dfrac{-3}{5}.\dfrac{6}{7}\)

\(=\dfrac{-3}{5}.\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)\)

\(=\dfrac{-3}{5}.2\)

\(=\dfrac{-6}{5}\)

c) \(10\dfrac{2}{9}+\left(2\dfrac{2}{5}-7\dfrac{2}{9}\right)\)

\(=\dfrac{92}{9}+\dfrac{12}{5}-\dfrac{65}{9}\)

\(=\dfrac{92}{9}-\dfrac{65}{9}+\dfrac{12}{5}\)

\(=3+\dfrac{12}{5}\)

\(=\dfrac{15}{5}+\dfrac{12}{5}\)

\(=\dfrac{27}{5}\)

d) \(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)

\(=\dfrac{63}{10}-\dfrac{25}{7}-\dfrac{23}{10}\)

\(=\dfrac{63}{10}-\dfrac{23}{10}-\dfrac{25}{7}\)

\(=4-\dfrac{25}{7}\)

\(=\dfrac{28}{7}-\dfrac{25}{7}\)

\(=\dfrac{3}{7}\)

Chúc bạn học tốt

a) \(\left(\dfrac{7}{8}-\dfrac{3}{4}\right).1\dfrac{1}{3}-\dfrac{2}{3}.0,5\)

\(=\left(\dfrac{7}{8}-\dfrac{6}{8}\right).\dfrac{4}{3}-\dfrac{2}{3}.\dfrac{1}{2}\)

\(=\dfrac{1}{8}.\dfrac{4}{3}-\dfrac{2}{3}.\dfrac{1}{2}\)

\(=\dfrac{1}{6}-\dfrac{1}{3}\)

\(=\dfrac{-1}{6}\)

b) \(\left(2+\dfrac{5}{6}\right):1\dfrac{1}{5}+\dfrac{-7}{12}\)

\(=\left(\dfrac{12}{6}+\dfrac{5}{6}\right):\dfrac{6}{5}+\dfrac{-7}{12}\)

\(=\dfrac{17}{6}.\dfrac{5}{6}+\dfrac{-7}{12}\)

\(=\dfrac{85}{36}+\dfrac{-7}{12}\)

\(=\dfrac{16}{9}\)

c) \(75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}\)

\(=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{1}{2}.\dfrac{12}{5}\)

\(=\dfrac{3}{4}-\dfrac{6}{4}+\dfrac{6}{5}\)

\(=\dfrac{-3}{4}+\dfrac{6}{5}\)

\(=\dfrac{9}{20}\)

\(150-\left(5.x-25\right)=50\)

\(5.x-25=150-50\)

\(5.x-25=100\)

\(5.x=100+25\)

\(5.x=125\)

\(x=125:5\)

\(x=25\)

a) \(\dfrac{-5}{11}+\left(\dfrac{-6}{11}+1\right)\)

\(=\dfrac{-5}{11}+\left(\dfrac{-6}{11}+\dfrac{11}{11}\right)\)

\(=\dfrac{-5}{11}+\dfrac{5}{11}\)

\(=0\)

b) \(\dfrac{2}{3}+\left(\dfrac{5}{7}+\dfrac{-2}{3}\right)\)

\(=\dfrac{2}{3}+\dfrac{-2}{3}+\dfrac{5}{7}\)

\(=0+\dfrac{5}{7}\)

\(=\dfrac{5}{7}\)

c) \(\left(\dfrac{-1}{4}+\dfrac{5}{8}\right)+\dfrac{-3}{8}\)

\(=\dfrac{-1}{4}+\dfrac{-3}{8}+\dfrac{5}{8}\)

\(=\dfrac{-2}{8}+\dfrac{-3}{8}+\dfrac{5}{8}\)

\(=0\)

d) \(\dfrac{3}{4}.\dfrac{7}{25}+\dfrac{3}{4}.\dfrac{18}{25}\)

\(=\dfrac{3}{4}.\left(\dfrac{7}{25}+\dfrac{18}{25}\right)\)

\(=\dfrac{3}{4}.1\)

\(=\dfrac{3}{4}\)

Chúc bạn học tốt

\(x+\dfrac{5}{4}=\dfrac{15}{4}:3\)

\(x+\dfrac{5}{4}=\dfrac{5}{4}\)

\(x=\dfrac{5}{4}-\dfrac{5}{4}\)

\(x=0\)

\(\dfrac{15}{2}-\left(2\times x+\dfrac{4}{3}\right)=\dfrac{5}{4}\)

\(2\times x+\dfrac{4}{3}=\dfrac{15}{2}-\dfrac{5}{4}\)

\(2\times x+\dfrac{4}{3}=\dfrac{25}{4}\)

\(2\times x=\dfrac{25}{4}-\dfrac{4}{3}\)

\(2\times x=\dfrac{59}{12}\)

\(x=\dfrac{59}{12}:2=\dfrac{59}{12}\times\dfrac{1}{2}\)

\(x=\dfrac{59}{24}\)

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