tìm x
12,3-2x(x+1,3)=5,7
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23,4 + \(x\) : 0,2 = 25,3
\(x:\) 0,2 = 25,3 - 23,4
\(x\) : 0,2 = 1,9
\(x\) = 1,9 x 0,2
\(x\) =
Vậy \(x=0,38\)
a; - \(\dfrac{3}{5}\) + \(\dfrac{7}{5}\) = \(\dfrac{-3+7}{5}\) = \(\dfrac{4}{5}\)
b; \(\dfrac{3}{5}\) - \(\dfrac{-9}{5}\) = \(\dfrac{3-\left(-9\right)}{5}\) = \(\dfrac{3+9}{5}\) = \(\dfrac{12}{5}\)
c; \(\dfrac{23}{-11}\) - \(\dfrac{-3}{11}\) = \(\dfrac{-23}{11}\) + \(\dfrac{3}{11}\) = \(\dfrac{-20}{11}\)
d; -2\(\dfrac{1}{3}\) - 1\(\dfrac{3}{4}\)
= \(\dfrac{-7}{3}\) - \(\dfrac{7}{4}\)
= \(\dfrac{-28}{12}\) - \(\dfrac{21}{12}\)
= \(\dfrac{-49}{12}\)
e; (- \(\dfrac{1}{3}\))(-\(\dfrac{9}{13}\))
= \(\dfrac{3}{13}\)
f; 1\(\dfrac{1}{2}\) x (- \(\dfrac{10}{9}\))
= \(\dfrac{3}{2}\) x (- \(\dfrac{10}{9}\))
= - \(\dfrac{5}{3}\)
\(64=8^2;100=10^2\)
\(121=11^2\)
\(169=13^2\)
\(196=14^2\)
\(289=17^2\)
\(\dfrac{1}{2}\)\(x^2\) = \(\dfrac{1}{4}x^2\) + \(\dfrac{1}{4}\)\(x^2\)
a: \(2\cdot3\cdot6\cdot6\cdot6=6\cdot6\cdot6\cdot6=6^4\)
b: \(4\cdot4\cdot5\cdot5\cdot5=4^2\cdot5^3\)
\(12,3-2\left(x+1,3\right)=5,7\)
\(2\left(x+1,3\right)=12,3-5,7\)
\(2\left(x+1,3\right)=6,6\)
\(x+1,3=6,6:2\)
\(x+1,3=3,3\)
\(x=3,3-1,3\)
\(x=2\)
`12,3 - 2× (x + 1,3) = 5,7`
`2× (x + 1,3) = 12,3 - 5,7`
`2× (x + 1,3) = 6,6`
`x + 1,3 = 6,6 : 2`
`x + 1,3 = 3,3`
`x = 3,3 - 1,3`
`x = 2`
Vậy...