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TH1: \(-5\le x\le2\)
=> \(\left(2-x\right)-4\left(5+x\right)=-23\)
\(=>2-x-20-4x=-23\)
\(=>-5x-18=-23\\ =>-5x=-23+18\\ =>-5x=-5\\ =>x=\dfrac{-5}{-5}=1\left(tm\right)\)
TH2: \(x>2\)
\(\left(x-2\right)-4\left(5+x\right)=-23\)
\(=>x-2-20-4x=-23\\ =>-3x-22=-23\\ =>-3x=-1\\ =>x=-\dfrac{1}{-3}=\dfrac{1}{3}\left(ktm\right)\)
TH3: \(x< -5\)
\(\left(2-x\right)+4\left(5+x\right)=-23\\ =>2-x+20+4x=-23\\ =>3x+22=-23\\ =>3x=-45\\ =>x=-15\left(tm\right)\)
Vậy: ...
$|2-x|-4|5+x|=-23$ (1)
+, Với $x< -5\Rightarrow \begin{cases} |2-x|=2-x\\|5+x|=-5-x \end{cases}$, (1) trở thành:
$2-x-4(-5-x)=-23$
$\Rightarrow 2-x+20+4x=-23$
$\Rightarrow 3x+22=-23$
$\Rightarrow 3x=-23-22$
$\Rightarrow 3x=--45$
$\Rightarrow x=-15$ (tmdk)
+, Với $-5\le x\le 2\Rightarrow \begin{cases} |2-x|=2-x\\|5+x|=5+x \end{cases}$, (1) trở thành:
$2-x-4(5+x)=-23$
$\Rightarrow 2-x-20-4x=-23$
$\Rightarrow -5x-18=-23$
$\Rightarrow -5x=-23+18$
$\Rightarrow -5x==-5$
$\Rightarrow x=1$ (tmdk)
+, Với $x>2\Rightarrow \begin{cases} |2-x|=x-2\\|5+x|=5+x \end{cases}$, (1) trở thành:
$x-2-4(5+x)=-23$
$\Rightarrow x-2-20-4x=-23$
$\Rightarrow -3x-22=-23$
$\Rightarrow -3x=-23+22$
$\Rightarrow -3x=-1$
$\Rightarrow x=\frac13$ (loại)
Vậy: ...
1) 15.9^3 : 27 - 6^2.12 +18.41
= 15.729 : 27 - 36.12 +738
= 10935 : 27 - 432 + 738
= 405 - 432 + 738
= 711
2) 18.7^3 + 9.2^6 :8 - 12.7
= 18.343 + 9.64 :8 - 84
= 6174 + 72 - 84
= 6162
3) 23.2^5 + 288.4^2 :12
= 23.32 + 288.16 :12
= 736 + 384
= 1120
4) 12^2 : 36 + 8^2 : 4 - 5.3
= 144 : 36 + 64 : 4 - 15
= 4 + 16 - 15
= 5
\(x+10\%\cdot x+20\%\cdot x+30\%\cdot x=4,8\)
=>\(x\left(1+0,1+0,2+0,3\right)=4,8\)
=>\(x\cdot1,6=4,8\)
=>\(x=4.8:1.6=3\)
\(B=\left[\left(-0,5\right):0,07-0,2:0,07\right]\cdot1,5-2024^0\\ =\left[\left(-0,5\right):\dfrac{7}{100}-0,2:\dfrac{7}{100}\right]\cdot1,5-1\\ =\left[\left(-0,5\right)\cdot\dfrac{100}{7}-0,2\cdot\dfrac{100}{7}\right]\cdot1,5-1\\ =\dfrac{100}{7}\cdot\left(-0,5-0,2\right)\cdot1,5-1\\ =\dfrac{100}{7}\cdot-0,7\cdot1,5-1\\ =\dfrac{100}{7}\cdot\dfrac{-7}{10}\cdot1,5-1\\ =-10\cdot1,5-1\\ =-15-1\\ =-16\)
\(1+3+5+...+x=36\\\left[ \left(x-1\right):2+1\right]\cdot\left(x+1\right):2=36\\ \dfrac{x-1+2}{2}\cdot\dfrac{x+1}{2}=36\\ \dfrac{x+1}{2}\cdot\dfrac{x+1}{2}=36\\ \dfrac{\left(x+1\right)^2}{4}=36\\ \left(x+1\right)^2=36\cdot4=144\)
TH1: x + 1 = 12 => x = 11
TH2: x + 1 = -12 => x = -13
Vì: x phải lớn hơn 0 => x = 11
1. Jane is wearing red shorts.
2. Tom is wearing black shoes.
3. Ken is wearing green trousers.
4. Sue is wearing a red shirt.
5. Elly is wearing an orange dress.
6. Jack is wearing blue socks.
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