\(a.\dfrac{3}{4}:x=-\dfrac{1}{2}\\ x=\dfrac{3}{4}:\left(-\dfrac{1}{2}\right)\\ x=-\dfrac{3}{2}\\ b.x:\left(-\dfrac{2}{3}\right)=-\dfrac{5}{6}\\ x=\left(-\dfrac{5}{6}\right)\cdot\left(-\dfrac{2}{3}\right)\\ x=\dfrac{5}{9}\\ c.\dfrac{1}{2}:x-\dfrac{1}{2}=-\dfrac{3}{4}\\ \dfrac{1}{2}:x=-\dfrac{1}{4}\\ x=\dfrac{1}{2}:\left(-\dfrac{1}{4}\right)\\ x=-2\\ d.\dfrac{1}{2}\cdot x+\dfrac{3}{4}=-\dfrac{5}{6}\\ \dfrac{1}{2}\cdot x=-\dfrac{19}{12}\\ x=\dfrac{-19}{12}:\dfrac{1}{2}=-\dfrac{19}{12}\cdot2\\ x=-\dfrac{19}{6}\)

\(e.x:\dfrac{1}{2}+\dfrac{1}{2}=-\dfrac{5}{6}\\ x:\dfrac{1}{2}=-\dfrac{4}{3}\\ x=-\dfrac{4}{3}\cdot\dfrac{1}{2}\\ x=-\dfrac{2}{3}\\ g.\dfrac{4}{3}-\dfrac{1}{2}\cdot x=\dfrac{1}{2}\\ \dfrac{1}{2}\cdot x=\dfrac{5}{6}\\ x=\dfrac{5}{6}:\dfrac{1}{2}=\dfrac{5}{6}\cdot2\\ x=\dfrac{5}{3}\\ h.\dfrac{3}{8}\cdot x-\dfrac{1}{2}=\dfrac{3}{4}\\ \dfrac{3}{8}\cdot x=\dfrac{1}{4}\\ x=\dfrac{1}{4}:\dfrac{3}{8}=\dfrac{1}{4}\cdot\dfrac{8}{3}\\ x=\dfrac{2}{3}\)

mình làm lại câu h xíu

\(\dfrac{3}{8}\cdot x-\dfrac{1}{2}=\dfrac{3}{4}\\ \dfrac{3}{8}\cdot x=\dfrac{5}{4}\\ x=\dfrac{5}{4}:\dfrac{3}{8}=\dfrac{5}{4}\cdot\dfrac{8}{3}\\ x=\dfrac{10}{3}\)

\(a.\dfrac{3}{2}-4\cdot\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\\ =\dfrac{3}{2}-4\cdot\dfrac{5}{4}\\ =\dfrac{3}{2}-5=-\dfrac{7}{2}\\ b.\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)\cdot11-7\\ =\dfrac{1}{2}\cdot11-7\\ =\dfrac{11}{2}-7=-\dfrac{3}{2}\\ c.\left(\dfrac{5}{8}+\dfrac{-2}{7}\right):\dfrac{3}{4}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right):\dfrac{3}{4}\\ =\left(\dfrac{5}{8}+\dfrac{-2}{7}\right)\cdot\dfrac{4}{3}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right)\cdot\dfrac{4}{3}\\ =\dfrac{4}{3}\cdot\left(\dfrac{5}{8}-\dfrac{2}{7}+\dfrac{3}{8}-\dfrac{5}{7}\right)\)

\(\dfrac{4}{3}\cdot\left[\left(\dfrac{5}{8}+\dfrac{3}{8}\right)-\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\right]\\ =\dfrac{4}{3}\cdot\left(1-1\right)=\dfrac{4}{3}\cdot0=0\)

\(d.\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\\ =\dfrac{3\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}=\dfrac{3}{13}\)

a) 

\(\dfrac{3}{2}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\\ =\dfrac{3}{4}-4\left(\dfrac{2}{4}+\dfrac{3}{4}\right)\\ =\dfrac{3}{4}-4\cdot\dfrac{5}{4}\\ =\dfrac{3}{4}-5\\ =-\dfrac{17}{4}\) 

b) 

\(\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)\times11-7\\ =\left(-\dfrac{2}{6}+\dfrac{5}{6}\right)\times11-7\\ =\dfrac{1}{2}\times11-7\\ =\dfrac{11}{2}-7\\ =-\dfrac{3}{2}\)

c) 

\(\left(\dfrac{5}{8}+\dfrac{-2}{7}\right):\dfrac{3}{4}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right):\dfrac{3}{4}\\ =\left(\dfrac{5}{8}+\dfrac{-2}{7}\right)\times\dfrac{4}{3}+\left(\dfrac{3}{8}-\dfrac{5}{7}\right)\times\dfrac{4}{3}\\ =\dfrac{4}{3}\times\left(\dfrac{5}{8}+\dfrac{-2}{7}+\dfrac{3}{8}-\dfrac{5}{7}\right)\times\dfrac{4}{3}\\ =\left(1-1\right)\times\dfrac{4}{3}\\ =0\times\dfrac{4}{3}\\ =0\)

d) 

\(M=\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\\ =\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}\\ =\dfrac{3}{13}\)

\(a.\left(-\dfrac{9}{34}\right)\cdot\dfrac{17}{4}=-\dfrac{9}{8}\\ b.\left(-\dfrac{20}{41}\right)\cdot\left(-\dfrac{4}{5}\right)=\dfrac{16}{41}\\ c.1\dfrac{1}{7}\cdot\left(-3\dfrac{1}{2}\right)=\dfrac{8}{7}\cdot\left(-\dfrac{7}{2}\right)=-4\\ d.\left(-\dfrac{5}{2}\right):\dfrac{3}{4}=\left(-\dfrac{5}{2}\right)\cdot\dfrac{4}{3}=-\dfrac{10}{3}\\ e.\left(-\dfrac{3}{4}\right):\left(-1\dfrac{1}{3}\right)=\left(-\dfrac{3}{4}\right)\cdot\left(-\dfrac{3}{4}\right)=\dfrac{9}{16}\\ g.\left(-5\right):\left(-2\dfrac{1}{2}\right)=\left(-5\right)\cdot\left(-\dfrac{2}{5}\right)=2\)

\(a)-\dfrac{9}{34}\times\dfrac{17}{4}\\ =\dfrac{-9}{17\times2}\times\dfrac{17}{4}\\ =\dfrac{-9}{8}\\ b)-\dfrac{20}{41}\times-\dfrac{4}{5}\\ =\dfrac{4\times5}{41}\times\dfrac{-4}{5}\\ =-\dfrac{16}{41}\\ c)1\dfrac{1}{7}\times\left(-3\dfrac{1}{2}\right)\\ =\dfrac{8}{7}\times\dfrac{-7}{2}\\ =-4\\ d)-\dfrac{5}{2}:\dfrac{3}{4}\\ =-\dfrac{5}{2}\times\dfrac{4}{3}\\ =\dfrac{-10}{3}\\ e)-\dfrac{3}{4}:\left(-1\dfrac{1}{3}\right)\\ =-\dfrac{3}{4}:-\dfrac{4}{3}\\ =-\dfrac{3}{4}\times-\dfrac{3}{4}\\ =\dfrac{9}{16}\\ g)-5:\left(-2\dfrac{1}{2}\right)\\ =-5:-\dfrac{5}{2}\\ =-5\times-\dfrac{2}{5}\\ =2\)

Số chữ số cần dùng để đánh số cho trang có 1 chữ số là:

(9-1+1)x1=9(chữ số)

Số chữ số cần dùng để đánh số cho trang có 2 chữ số là:

(99-10+1)x2=180(chữ số)

SỐ chữ số cần dùng để đánh số cho trang có 3 chữ số là:
(100-100+1)x3=3(chữ số)

Số chữ số cần dùng là:

9+180+3=192(chữ số)

Lời giải:

a.

$4x^2-6x=0$

$\Leftrightarrow 2x(2x-3)=0$

$\Leftrightarrow 2x=0$ hoặc $2x-3=0$

$\Leftrightarrow x=0$ hoặc $x=\frac{3}{2}$

b.

$9x^2-6x+1=0$

$\Leftrightarrow (3x-1)^2=0$

$\Leftrightarrow 3x-1=0$

$\Leftrightarrow x=\frac{1}{3}$

c.

$x^2-25=x+5$

$\Leftrightarrow (x-5)(x+5)=x+5$

$\Leftrightarrow (x+5)(x-5-1)=0$

$\Leftrightarrow (x+5)(x-6)=0$

$\Leftrightarrow x+5=0$ hoặc $x-6=0$

$\Leftrightarrow x=-5$ hoặc $x=6$

d.

$(5x-3)^2=(5-3x)^2$

$\Leftrightarrow (5x-3)^2-(5-3x)^2=0$

$\Leftrightarrow (5x-3-5+3x)(5x-3+5-3x)=0$

$\Leftrightarrow (2x-8)(2x+2)=0$

$\Leftrightarrow 2x-8=0$ hoặc $2x+2=0$

$\Leftrightarrow x=4$ hoặc $x=-1$

\(B=9a^2+12a\)

\(=9a^2+12a+4-4\)

\(=\left(3a+2\right)^2-4>=-4\forall a\)

Dấu '=' xảy ra khi 3a+2=0

=>\(a=-\dfrac{2}{3}\)

Bài 9:

a: Số số hạng là \(\dfrac{100-2}{2}+1=\dfrac{98}{2}+1=50\left(số\right)\)

Tổng của dãy số là \(A=\dfrac{\left(100+2\right)\cdot50}{2}=102\cdot25=2550\)

b: \(B=2020-2019+2018-2017+...+2-1\)

=(2020-2019)+(2018-2017)+...+(2-1)

=1+1+...+1

=1010

Bài 8:

Số chuyến bay trong tháng 1 là:

8795+125=8920(chuyến)

Số chuyến bay cần đạt được trong tháng 3 là:

27000-8795-8920=9285(chuyến)

Bài 4:

a: x+1999=2021

=>x=2021-1999

=>x=22

b: \(1152-x=1138\)

=>x=1152-1138

=>x=14

c: \(125-\left(x+4\right)=35\)

=>x+4=125-35=90

=>x=90-4=86

d: \(1270+\left(442-x\right)=1480\)

=>442-x=1480-1270=210

=>x=442-210=232

Bài 5:

Độ dài quãng đường từ Hà Nội đến Vân Đồn là:

58+92+60=210(km)

Đặt $A=99-97+95-93+91-89+...+7-5+3-1$ (sửa đề)

$=(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1)$

$=2+2+2+...+2+2$

Số các số 2 trong dãy số trên là: $[(99-1):2+1]:2=25$ (số)

Do đó: $A=2.25=50$

Sửa đề: 99-97+95-93+...+7-5+3-1

=(99-97)+(95-93)+...+(7-5)+(3-1)

=2+2+...+2

=2x25=50

$24.25+2.38.12+3.8.37$

$=24.25+(2.12).38+(3.8).37$

$=24.25+24.38+24.37$

$=24.(25+38+37)$

$=24.(63+37)$

$=24.100=2400$

24 . 25 + 2 . 38 . 12 + 3 . 8 . 37

= 24 . 25 + ( 2 . 12 ) . 38 + ( 3 . 8 ) . 37

= 24 . 25 + 24 . 38 + 24 . 37

= 24 . ( 25 + 38 + 37 )

= 24 . 100

= 2400