d,

\(a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\left(a+b\right)\)

\(=\left(a+b\right)\left(a+b-c\right)\)

Vậy..

e

\(x^2-2x-4y^2-4y\)

\(=\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y+1\right)^2\)

\(=\left(x-2y-2\right)\left(x+2y\right)\)

a)\(x^2-y^2-2x+2y=\left(x^2-2x+1\right)-\left(y^2-2y+1\right)\)

\(=\left(x-1\right)^2-\left(y-1\right)^2=\left(x-1+y-1\right)\left(x-1-y+1\right)\)

\(=\left(x+y-2\right)\left(x-y\right)\)

b)\(3a^2-6ab+3b^2-12c^2=3\left(a^2-2ab+b^2-4c^2\right)\)\(=3\left[\left(a-b\right)^2-\left(2c\right)^2\right]\)

\(=3\left(a-b+2c\right)\left(a-b-2c\right)\)

d

\(x^4+2x^3-4x-4\)

\(=\left(x^4+2x^3+x^2\right)-\left(x^2+4x+4\right)\)

\(=\left(x^2+x\right)^2-\left(x+2\right)^2\)

\(=\left(x^2-2\right)\left(x^2+2x+2\right)\)

1, arranging flower

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3, listening to music

\(x^2\left(x-1\right)-\left(4x^2-8x+4\right)\) ( đề nhầm ) 

\(=\)\(x^2\left(x-1\right)-4\left(x^2-2x+1\right)\)

\(=\)\(x^2\left(x-1\right)-4\left(x-1\right)^2\)

\(=\)\(\left(x-1\right)\left(x^2-4x+4\right)\)

\(=\)\(\left(x-1\right)\left(x-2\right)^2\)

Chúc bạn học tốt ~ 

\(\left(2x-3\right)^2=\left(x+5\right)^2\)

\(\Leftrightarrow\)\(\left(2x-3\right)^2-\left(x+5\right)^2=0\)

\(\Leftrightarrow\)\(\left(2x-3-x-5\right)\left(2x-3+x+5\right)=0\)

\(\Leftrightarrow\)\(\left(x-8\right)\left(3x+2\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x-8=0\\3x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x=\frac{-2}{3}\end{cases}}}\)

Vậy \(x=8\) hoặc \(x=\frac{-2}{3}\)

Chúc bạn học tốt ~ 

Phùng Minh Quân: Mình mới lớp 7 nên chưa hiểu cách của bạn. Nên mình giải lại theo cách của mình nhé!

\(\left(2x-3\right)^2=\left(x+5\right)^2\)

\(\Rightarrow\orbr{\begin{cases}2x-3=x+5\\-\left(2x-3\right)=-\left(x+5\right)\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x-x=8\\2x+3=x-5\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=8\\2x+3=5+\left(-x\right)\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=8\\2x+x=3+\left(-5\right)\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=8\\3x=-2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=8\\x=-\frac{2}{3}\end{cases}}\)

ấn vào câu hỏi tương tự ấy 

https://olm.vn/hoi-dap/question/1004845.html