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Câu 1: B

Câu 2: D

Câu 3: B

Câu 4: C

Câu 5: A

Câu 6: B

Câu 7: C

Câu 8: B

Câu 9: C

Câu 10: D

Câu 11: D

Câu 12: C

Bài 1:

a: \(\dfrac{7}{30}+\dfrac{-12}{37}+\dfrac{23}{30}+\dfrac{-25}{37}\)

\(=\left(\dfrac{7}{30}+\dfrac{23}{30}\right)+\left(-\dfrac{12}{37}-\dfrac{25}{37}\right)\)

\(=\dfrac{30}{30}+\dfrac{-37}{37}=1-1=0\)

b: \(\dfrac{-20}{23}+\dfrac{8}{15}-\dfrac{3}{23}+\dfrac{7}{15}+\dfrac{1}{2}\)

\(=\left(-\dfrac{20}{23}-\dfrac{3}{23}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)+\dfrac{1}{2}\)

\(=-1+1+\dfrac{1}{2}=\dfrac{1}{2}\)

c: \(\left(-12,5\right)+17,55+\left(-3,5\right)+2,45\)

\(=\left(-12,5-3,5\right)+\left(17,55+2,45\right)\)

=20-16

=4

d: \(\left(-9,237\right)+3,8+1,237-3,8+1,123\)

\(=\left(-9,237+1,237\right)+\left(3,8-3,8\right)+1,123\)

=-8+1,123

=-6,877

e: \(4,35-\left(2,67-1,65\right)+\left(3,54-6,33\right)\)

\(=4,35-2,67+1,65+3,54-6,33\)

\(=6-9+3,54=3,54-3=0,54\)

g: \(\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}-\dfrac{5}{7}\cdot\dfrac{14}{11}\)

\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=-\dfrac{5}{11}\)

h: \(\dfrac{-5}{7}\cdot\dfrac{3}{13}+\dfrac{-5}{7}\cdot\dfrac{10}{13}+1\dfrac{5}{7}\)

\(=-\dfrac{5}{7}\left(\dfrac{3}{13}+\dfrac{10}{13}\right)+\dfrac{12}{7}=-\dfrac{5}{7}+\dfrac{12}{7}=\dfrac{7}{7}=1\)

i: \(3,58\cdot24,45+3,58\cdot75,55+12,42\)

\(=3,58\left(24,45+75,55\right)+12,42\)

\(=358+12,42=370,42\)

k: \(3,4\cdot\left(-23,68\right)-3,4\cdot45,12+\left(-31,2\right)\cdot3,4\)

\(=3,4\left(-23,68-45,12-31,2\right)\)

\(=3,4\cdot\left(-100\right)=-340\)

l: \(1,14\cdot6,4+1,14\cdot3,6+11,4\)

\(=1,14\left(6,4+3,6\right)+1,14\cdot10\)

\(=1,14\cdot20=22,8\)

Giúp mk với!

Nửa chu vi hình chữ nhật là 18:2=9(cm)

Chu vi không đổi thì nửa chu vi cũng không đổi

Tỉ số giữa chiều dài mới so với chiều dài cũ là:

100%-20%=0,8

Tỉ số giữa chiều rộng mới so với chiều rộng cũ là:

25%+100%=125%=1,25

0,8xchiềudài+1,25x chiều rộng=9

=>chiều dài+1,5625 chiều rộng=11,25

mà chiều dài+chiều rộng=9

nên 0,5625 lần chiều rộng là 11,25-9=2,25

=>Chiều rộng là 2,25:0,5625=4(cm)

=>Chiều dài là 9-4=5(cm)

Diện tích hình chữ nhật là \(5\cdot4=20\left(cm^2\right)\)

9: \(A=\dfrac{3^2}{10}+\dfrac{3^2}{40}+...+\dfrac{3^2}{340}\)

\(=3\left(\dfrac{3}{10}+\dfrac{3}{40}+...+\dfrac{3}{340}\right)\)

\(=3\left(\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+...+\dfrac{3}{17\cdot20}\right)\)

\(=3\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{17}-\dfrac{1}{20}\right)\)

\(=3\left(\dfrac{1}{2}-\dfrac{1}{20}\right)=3\cdot\dfrac{9}{20}=\dfrac{27}{20}\)

10: \(A=\dfrac{5^2}{1\cdot6}+\dfrac{5^2}{6\cdot11}+...+\dfrac{5^2}{26\cdot31}\)

\(=5\left(\dfrac{5}{1\cdot6}+\dfrac{5}{6\cdot11}+...+\dfrac{5}{26\cdot31}\right)\)

\(=5\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+...+\dfrac{1}{25}-\dfrac{1}{31}\right)\)

\(=5\left(1-\dfrac{1}{31}\right)=5\cdot\dfrac{30}{31}=\dfrac{150}{31}\)

11: \(A=\dfrac{6}{15}+\dfrac{6}{35}+\dfrac{6}{63}+\dfrac{6}{99}\)

\(=3\left(\dfrac{2}{15}+\dfrac{2}{35}+\dfrac{2}{63}+\dfrac{2}{99}\right)\)

\(=3\left(\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+\dfrac{2}{7\cdot9}+\dfrac{2}{9\cdot11}\right)\)

\(=3\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right)\)

\(=3\left(\dfrac{1}{3}-\dfrac{1}{11}\right)=3\cdot\dfrac{8}{33}=\dfrac{8}{11}\)

12: \(A=\dfrac{3}{3\cdot5}+\dfrac{3}{5\cdot7}+...+\dfrac{3}{49\cdot51}\)

\(=\dfrac{3}{2}\left(\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+...+\dfrac{2}{49\cdot51}\right)\)

\(=\dfrac{3}{2}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{49}-\dfrac{1}{51}\right)\)
\(=\dfrac{3}{2}\left(\dfrac{1}{3}-\dfrac{1}{51}\right)=\dfrac{3}{2}\cdot\dfrac{16}{51}=\dfrac{8}{17}\)

13: \(A=\dfrac{1}{2}+\dfrac{2}{2\cdot4}+\dfrac{3}{4\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{5}{11\cdot16}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}\)

\(=1-\dfrac{1}{16}=\dfrac{15}{16}\)

14: \(A=\dfrac{1}{2}+\dfrac{2}{8}+\dfrac{3}{28}+\dfrac{4}{77}+\dfrac{5}{176}\)

\(=\dfrac{1}{1\cdot2}+\dfrac{2}{2\cdot4}+\dfrac{3}{4\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{5}{11\cdot16}\)

15: \(A=\dfrac{3}{54}+\dfrac{5}{126}+\dfrac{7}{294}+\dfrac{8}{609}\)

\(=\dfrac{3}{6\cdot9}+\dfrac{5}{9\cdot14}+\dfrac{7}{14\cdot21}+\dfrac{8}{21\cdot29}\)

\(=\dfrac{1}{6}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{29}\)

\(=\dfrac{1}{6}-\dfrac{1}{29}=\dfrac{23}{174}\)

16: \(A=\dfrac{5}{24}+\dfrac{5}{104}+\dfrac{5}{234}+\dfrac{5}{414}\)

\(=\dfrac{5}{3\cdot8}+\dfrac{5}{8\cdot13}+\dfrac{5}{13\cdot18}+\dfrac{5}{18\cdot23}\)

\(=\dfrac{1}{3}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{23}\)

\(=\dfrac{1}{3}-\dfrac{1}{23}=\dfrac{20}{69}\)

17: \(A=\dfrac{\dfrac{3}{54}+\dfrac{5}{126}+\dfrac{7}{294}}{\dfrac{5}{24}+\dfrac{5}{104}+\dfrac{5}{234}}\)

\(=\dfrac{\dfrac{1}{6}-\dfrac{1}{21}}{\dfrac{1}{3}-\dfrac{1}{18}}=\dfrac{15}{126}:\dfrac{15}{54}=\dfrac{54}{126}=\dfrac{3}{7}\)

vì khi chúng ta bật quạt, điện năng đã chuyển thành dạng năng lượng nhiệt năng khiến chúng ta thấy mát mẻ

bật quạt lên thì chúng ta sẽ được gió thổi đi hơi nóng trong người và nhiệt xung quanh người làm nhiệt độ trong người giảm xuống và chúng ta sẽ mát hơn

1: \(\left(-12,5\right)+17,55+\left(-3,5\right)-\left(-2,45\right)\)

\(=\left(-12,5-3,5\right)+17,55+2,45\)

=-16+20

=4

2: \(\dfrac{-3}{5}\cdot\dfrac{2}{7}+2\dfrac{3}{5}-\dfrac{3}{5}\cdot\dfrac{5}{7}\)

\(=-\dfrac{3}{5}\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{13}{5}\)

\(=-\dfrac{3}{5}+\dfrac{13}{5}=\dfrac{10}{5}=2\)

3: \(\dfrac{2}{3}:x=2,4-\dfrac{4}{5}\)

=>\(\dfrac{2}{3}:x=2,4-0,8=1,6\)

=>\(x=\dfrac{2}{3}:1,6=\dfrac{2}{4,8}=\dfrac{1}{2,4}=\dfrac{5}{12}\)