- Ta có: \(n_{NaOH\left(2M\right)}=0,5.2=1\left(mol\right)\)

Gọi V_{H2O thêm vào} = a (ml)

\(\Rightarrow V_{NaOH\left(1M\right)}=\dfrac{1}{1}=1\left(l\right)=1000\left(ml\right)=500+a\)

\(\Rightarrow a=500\left(ml\right)\)

- PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\) - pư hóa hợp.

\(Fe+2HCl\rightarrow FeCl_2+H_2\) - pư thế

b, \(n_{HNO_3}=0,5.0,2=0,1\left(mol\right)\)

\(\Rightarrow m_{HNO_3}=0,1.63=6,3\left(g\right)\)

d, \(n_{NaNO_3}=0,2.0,2=0,04\left(mol\right)\)

\(\Rightarrow m_{NaNO_3}=0,04.85=3,4\left(g\right)\)

Ta có: \(n_{KClO_3}=\dfrac{12,25}{122,5}=0,1\left(mol\right)\)

PT: \(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)

Theo PT: \(n_{KCl}=n_{KClO_3}=0,1\left(mol\right)\Rightarrow m_{KCl}=0,1.74,5=7,45\left(g\right)\)

\(n_{O_2}=\dfrac{3}{2}n_{KClO_3}=0,15\left(mol\right)\Rightarrow V_{O_2}=0,15.24,79=3,7185\left(l\right)\)

\(Mg+2HCl\rightarrow MgCl_2+H_2\\ 2Al+3Cl_2\rightarrow\left(t^o\right)2AlCl_3\\ 2H_2O\rightarrow\left(đp\right)2H_2+O_2\\ 2Al+3CuSO_4\rightarrow Al_2\left(SO_4\right)_3+3Cu\)

\(a,\\ Fe_2O_3+3H_2\rightarrow\left(t^o\right)2Fe+3H_2O\\ Fe_3O_4+4H_2\rightarrow\left(t^o\right)3Fe+4H_2O\)

Loại phản ứng: Phản ứng thế

\(b,n_{Fe}=2.n_{Fe_2O_3}+3.n_{Fe_3O_4}=2.\dfrac{32}{160}+3.0,15=0,85\left(mol\right)\\ m_{Fe}=0,85.56=47,6\left(g\right)\\ c,n_{H_2}=\dfrac{32}{160}.3+4.0,15=1,2\left(mol\right)\\ V_{H_2\left(đktc\right)}=1,2.22,4=28\left(l\right)\)

Em xem sao oxit sắt lại hỏi KL nhôm nha! Vô lí!!!

Em c.ơn ạ

\(n_{Br_2}=\dfrac{28}{160}=0,175\left(mol\right)\\ a,C_2H_4+Br_2\rightarrow C_2H_4Br_2\\ b,n_{C_2H_4}=n_{Br_2}=0,175\left(mol\right)\\ V_{C_2H_4}=0,175.22,4=3,92\left(l\right)\\ \%V_{C_2H_4}=\dfrac{3,92}{8,6}.100\approx45,581\%\\ \%V_{CH_4}\approx54.419\%\)

c, Thiếu dữ kiện

Chuỗi 1:

\(\left(1\right)CaCO_3\rightarrow\left(t^o\right)CaO+CO_2\\ \left(2\right)CaO+3C\rightarrow\left(2000^oC,lò.điện\right)CaC_2+CO\uparrow\\ \left(3\right)CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\\ \left(4\right)C_2H_2+H_2\rightarrow\left(Ni,t^o\right)C_2H_4\\ \left(5\right)C_2H_4+H_2O\rightarrow\left(t^o,H^+\right)C_2H_5OH\\ \left(6\right)C_2H_5OH+2NaOH+CH_3COOH\rightarrow CH_3COONa+C_2H_5ONa+2H_2O\)

\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\ a,Zn+2HCl\rightarrow ZnCl_2+H_2\\ b,n_{ZnCl_2}=n_{Zn}=0,1\left(mol\right);n_{HCl}=2.0,1=0,2\left(mol\right)\\ m_{ZnCl_2}=136.0,1=13,6\left(g\right)\\ c,V_{ddHCl}=\dfrac{0,2}{2}=0,1\left(lít\right)\)