Cấm đăng câu hỏi linh tinh lên diễn đàn hoặc câu hỏi không thuộc phạm vi môn học nha bạn

Ko đăng câu hỏi linh tinh

Hok tốt

# MissyGirl #

TTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG

\(A=\sqrt{sin^2x-sin^2x.\frac{cos\text{ }x}{sin\text{ }x}+cos^2x-cos^2x.\frac{sin\text{ }x}{cos\text{ }x}}\)

\(A=\sqrt{\left(sin^2x+cos^2x\right)-\left(sin\text{ }x.cos\text{ }x-cos\text{ }x.sin\text{ }x\right)}\)

\(A=\sqrt{1}=1\)

\(A=\sqrt{\sin^2x\left(1-\cot x\right)+\cos^2x\left(1-\tan x\right)}\)

\(A=\sqrt{\sin^2x-\sin^2x\cot x+\cos^2x-\cos^2x\tan x}\)

\(A=\sqrt{1-\sin^2x\frac{\cos x}{\sin x}-\cos^2x\frac{\sin}{\cos}}\)

\(A=\sqrt{1-\sin x\cos x-\sin x\cos x}\)

\(A=\sqrt{\sin^2x-2\sin x\cos x+\cos^2x}\)

\(A=\sqrt{\left(\sin x-\cos x\right)^2}=\left|\sin x-\cos x\right|\)

bố ai mà bt đc

\(P=\sqrt{\left(x-1\right)^2+4}\ge\sqrt{4}=2\)

Dấu bằng cảy ra khi x=1

mk đếm đc là 29 hình

khó vl

hình như là 29 hình

đếm mãi ms đc