Gtnn =29

lớn hơn , bé hơn hoặc bằng dễ òm đi chịch hk cưng ?

ĐANG CẦN GẤP

là một con số nào đó đi chịch hk cưng ?

Ta có:[\(\frac{37}{99}\)+\(\frac{7}{9}\)]x=\(\frac{1}{6}\)

x=\(\frac{38}{33}\).x=\(\frac{1}{6}\)

x=\(\frac{1}{6}\):\(\frac{38}{33}\)

=>    x=\(\frac{11}{76}\)

\(\frac{x+1}{2013}+\frac{x}{2012}+\frac{x-1}{2011}=\frac{x-2}{2010}+\frac{x-3}{2009}+\frac{x-4}{2008}\)

\(\Leftrightarrow\frac{x+1}{2013}-1+\frac{x}{2012}-1+\frac{x-1}{2011}-1=\frac{x-2}{2010}-1+\frac{x-3}{2009}-1+\frac{x-4}{2008}-1\)

\(\Leftrightarrow\frac{x-2012}{2013}+\frac{x-2012}{2012}+\frac{x-2012}{2011}=\frac{x-2012}{2010}+\frac{x-2012}{2009}+\frac{x-2012}{2008}\)

\(\Leftrightarrow\frac{x-2012}{2013}+\frac{x-2012}{2012}+\frac{x-2012}{2011}-\frac{x-2012}{2010}-\frac{x-2012}{2009}-\frac{x-2012}{2008}=0\)

\(\Leftrightarrow\left(x-2012\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\right)=0\)

\(\Leftrightarrow x-2012=0\). Do \(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\ne0\)

\(\Leftrightarrow x=2012\)

\(7^{2011}=7.7^{2010}=7.\left(49\right)^{1005}=7.49.\left(49\right)^{1004}=7.49.\left(....1\right)^{502}=7.49.\left(...1\right)=\left(...3\right)\)